Find distance traveled given electric field + vf and vi

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Homework Help Overview

The discussion revolves around a problem involving an electron moving through a uniform electric field, with given initial and final velocities. Participants are exploring the relationship between kinetic energy and electric potential energy to determine the distance traveled by the electron.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss equating kinetic energy and potential energy, questioning the validity of this approach. There are attempts to derive the distance using energy conservation and force equations, with some participants suggesting alternative methods involving acceleration.

Discussion Status

The discussion is active, with participants providing guidance on different approaches and questioning each other's reasoning. There is an exploration of the relationship between kinetic and potential energy, and some participants are reconsidering their initial assumptions based on feedback.

Contextual Notes

Participants are navigating potential flaws in their reasoning regarding energy conservation and the assumptions about initial and final energies. The context includes the specific conditions of the problem, such as the uniform electric field and the properties of the electron.

Shaif
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Homework Statement


Electric field= 425 N/C
Vf = 3.25x10^5 m/S
VI=0
The charge is an electron

Homework Equations


An electron gun had a uniform electric field. The electron starts from rest and is fired from the gun, reaching a speed of (vf given above). How far does the electron move relative to the electron field?

The Attempt at a Solution


Ek = .5 mv^2
Electric pot. Energy = -qed
Find intial energy at the end of the motion using .5mvf^2 then use it to solve for d by plugging it into Ee= -qed where D is the distance travelled?
 
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Not exactly, but close. What is your reasoning in putting Ekin = Epot?
 
Orodruin said:
Not exactly, but close. What is your reasoning in putting Ekin = Epot?
I'm assuming that the vf equals the electrons energy at the end is a complete energy transfer.

But I've talked to another teacher and what I should be doing is apparently this :

Fe= we
Fnet=ma
Fe=Fnet
Isolate for a
a=qe/m
Vf^2=vi^2 +2ad
Solve for D.
I believe this is righr
 
Shaif said:
I'm assuming that the vf equals the electrons energy at the end is a complete
I suggest you write down exactly what you would get and exactly what your motivation is for it to hold in terms of mathematical expressions. You can use energy arguments, but the way you have presented yours makes me suspect that you have a basic flaw in your reasoning. What do you get when you try to solve the problem?
 
Orodruin said:
I suggest you write down exactly what you would get and exactly what your motivation is for it to hold in terms of mathematical expressions. You can use energy arguments, but the way you have presented yours makes me suspect that you have a basic flaw in your reasoning. What do you get when you try to solve the problem?
If the flaw is that Eeinitial =/= Ekfinal but rather Eeinitial =/= Ekfinal + Eefinal but I'm assuming Ee is pretty much 0 but I can see how there's a flaw in that reasoning. That's why I guess the second approach where I use forces to calculate the acceleration and use vf^2=vi^2 +2ad would be a lot better
 
Shaif said:
If the flaw is that Eeinitial =/= Ekfinal but rather Eeinitial =/= Ekfinal + Eefinal
The total energy is conserved, but what does that tell you about the relation between the final kinetic energy and the final potential energy? The energy argument is much cleaner and simpler than the force argument.
 

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