Efficiency and Energy to move a box on a conveyor belt

  • #1
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Homework Statement:

Please refer to the attached picture.

Relevant Equations:

This is where I am stuck at, I can’t seem to figure out the formulas to use and the combination of using them.
BNuT1m6SNQp9NkuEX_uqpdE9Mzaiexp13KOhfix3YyAE3Q5Y5n9hPU6QqUzu2HeNAKFm5-L_5OpYv8QI0qRLzm_iCbtBNS...png
 
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Answers and Replies

  • #2
etotheipi
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What force acts on the box? I assume the conveyor belt is horizontal.
 
  • #4
etotheipi
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If the box is being accelerated by the belt, the belt's got to be exerting a force on it. You know the mass of the box (from the weight) and the acceleration, so can you get the force the belt exerts on the box?
 
  • #6
etotheipi
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Yeah, but you can just use components here. Just say ##F=ma##. What is the force?
 
  • #7
Would that be 350 x 2.78 to get 973 N as the force?
 
  • #8
etotheipi
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  • #9
Oops, that would be 35.7 kg. Then 35.7 x 2.78 to get 99.2 N
 
  • #10
haruspex
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Oops, that would be 35.7 kg. Then 35.7 x 2.78 to get 99.2 N
So how much work is done on the box in moving it the 100m?
 
  • #11
So how much work is done on the box in moving it the 100m?
I used f=ma to get 99.2N then I used W=fd to get 9920J. This energy is the output, so output/0.25=input. To get a final answer of 3.97 x 10^4 J This is correct?
 
  • #12
haruspex
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I used f=ma to get 99.2N then I used W=fd to get 9920J. This energy is the output, so output/0.25=input. To get a final answer of 3.97 x 10^4 J This is correct?
Looks good.
 

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