Efficiency and Energy to move a box on a conveyor belt

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Homework Help Overview

The discussion revolves around the forces acting on a box being moved by a conveyor belt, specifically focusing on the calculations of force, work, and energy involved in this scenario.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the forces acting on the box, including gravity and the force exerted by the conveyor belt. There are attempts to calculate the force using the mass and acceleration, as well as discussions on the work done in moving the box over a distance.

Discussion Status

Some participants have provided calculations for the force and work done, while others are verifying the values and methods used. There is an ongoing exploration of the relationships between force, work, and energy, with some guidance offered on the calculations.

Contextual Notes

Participants are working with specific values for mass and acceleration, and there is a mention of efficiency in the context of energy input and output. The discussion includes some repeated calculations and confirmations of values.

UnknownQuestioner
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Homework Statement
Please refer to the attached picture.
Relevant Equations
This is where I am stuck at, I can’t seem to figure out the formulas to use and the combination of using them.
BNuT1m6SNQp9NkuEX_uqpdE9Mzaiexp13KOhfix3YyAE3Q5Y5n9hPU6QqUzu2HeNAKFm5-L_5OpYv8QI0qRLzm_iCbtBNS...png
 
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What force acts on the box? I assume the conveyor belt is horizontal.
 
Gravity? Not sure
 
If the box is being accelerated by the belt, the belt's got to be exerting a force on it. You know the mass of the box (from the weight) and the acceleration, so can you get the force the belt exerts on the box?
 
1588848049429.png
 
Yeah, but you can just use components here. Just say ##F=ma##. What is the force?
 
Would that be 350 x 2.78 to get 973 N as the force?
 
UnknownQuestioner said:
Would that be 350 x 2.78 to get 973 N as the force?

What's the mass of the box?
 
Oops, that would be 35.7 kg. Then 35.7 x 2.78 to get 99.2 N
 
  • #10
UnknownQuestioner said:
Oops, that would be 35.7 kg. Then 35.7 x 2.78 to get 99.2 N
So how much work is done on the box in moving it the 100m?
 
  • #11
haruspex said:
So how much work is done on the box in moving it the 100m?

I used f=ma to get 99.2N then I used W=fd to get 9920J. This energy is the output, so output/0.25=input. To get a final answer of 3.97 x 10^4 J This is correct?
 
  • #12
UnknownQuestioner said:
I used f=ma to get 99.2N then I used W=fd to get 9920J. This energy is the output, so output/0.25=input. To get a final answer of 3.97 x 10^4 J This is correct?
Looks good.
 

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