Eigenvalues of Invertible Matrix

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An invertible nxn matrix does not necessarily have n distinct eigenvalues; it can have fewer distinct eigenvalues. The key point is that an invertible matrix must not have 0 as an eigenvalue, which implies that all eigenvalues must be non-zero. The discussion highlights the distinction between the total number of eigenvalues and the number of distinct eigenvalues. The unit nxn matrix is indeed invertible, and its eigenvalues are all equal to 1. Understanding these concepts is crucial for correctly addressing the properties of eigenvalues in relation to matrix invertibility.
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Homework Statement


If A is an invertible nxn matrix, then A has n distinct eigenvalues. (TRUE/ FALSE)



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The Attempt at a Solution


True? We weren't really taught the concept of eigenvalues too well, but from what I can gather square matrices appear to have the same number of eigenvalues as their number of rows/columns. I'm not sure why though.
 
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Is the unit nxn matrix invertible? What are its eigenvalues?
 
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"number of eigenvalues" and "number of distinct eigenvalues" are two entirely different things. As far as being "invertible" is concerned the only thing you can say is that a matrix is invertible if and only if it does not have 0 as an eigenvalue.
 

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