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Physics
Quantum Physics
Ejection of Only one electron by a Photon in the Photoelectric effect
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[QUOTE="ZapperZ, post: 6079435, member: 6230"] But that [B]original[/B] one photon that entered the material has now kicked out more than one electron. So that in itself has already answered your original question. But now comes the details, because, for example, how would we know that an Auger process took place? This is where one has to look at the [B]details[/B] of the emitted electron spectrum. The Auger process has a distinct spectrum where by it actually gives you info about the core level states. A "[URL='https://www.physicsforums.com/insights/anatomy-of-compton-scattering/']compton scattering[/URL]" does not, because the compton spectrum is typically broad! Besides, there's another important issue here. When an energetic electron bumps into another electron, this is a "lossy" process in terms of energy of the original electron. In fact, an electron that already has enough energy to escape a material will tend to lose that energy quite easily if it bumps into another electron before it escapes the material. This is why metals are usually poorer photocathodes than semiconductors, because metals have more free electrons than semiconductors. So a "compton process" inside a solid is often detrimental to the emission of electrons from that solid. Zz. [/QUOTE]
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Ejection of Only one electron by a Photon in the Photoelectric effect
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