Elasticity of a Tubular Cantilever Beam

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Discussion Overview

The discussion revolves around modeling a metal tube as a cantilever beam to determine its maximum deflection before reaching plasticity. The specific parameters include the material properties of 304 stainless steel and the geometric dimensions of the tube. Participants explore various aspects of the problem, including yield criteria, support conditions, and the influence of the surrounding plastic material.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant describes the setup of a metal tube modeled as a cantilever beam with specific dimensions and material properties, seeking guidance on calculating deflection.
  • Several participants inquire about the support conditions at the fixed end and the nature of the load application at the free end of the tube.
  • There is a discussion regarding the yield criterion being used, with one participant specifying the use of the von Mises criterion.
  • Concerns are raised about the potential for the plastic material to yield before the metal tube, given the interaction between the two materials.
  • Another participant emphasizes the importance of considering shear deflection due to the short length of the beam relative to its dimensions, suggesting that deflection will involve shear, bending, and deformation in the plastic.
  • A proposed mathematical approach is presented for calculating yield and deflection, though it is noted that the unusual dimensions of the beam may affect the accuracy of standard beam theory calculations.

Areas of Agreement / Disagreement

Participants express differing views on the yield behavior of the materials involved, particularly regarding whether the plastic will yield before the metal tube. The discussion remains unresolved with multiple competing perspectives on the influence of the plastic material and the appropriate modeling approach.

Contextual Notes

Participants note limitations in the applicability of standard beam theory due to the unusual dimensions of the beam and the complex interactions between the metal tube and the surrounding plastic material.

mechanic667
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I have a problem where I have a metal tube that I am modeling as a cantilever beam which is fixed at one end and has a point load at the other end. The material of this beam is 304 stainless steel, the inner diameter is 0.5mm, the outer diameter is 2mm, and the length of the beam is 4.15mm. With this I am trying to determine the maximum deflection of the beam before plasticity occurs. I have tried to find equations online to determine this point but am not finding much. Because I have the material of the beam, I have the elastic modulus, yield strength, and am able to calculate the moment of inertia. If anyone has any input on how to start solving this problem, that would be greatly appreciated!
 
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Welcome to PF. :smile:

How is the fixed end supported? Is the full circumference of the metal tube welded to a vertical metal wall? How is the load supported at the far end of the tube? Is there a plate welded to the end and the plate supports the weight of the load?
 
berkeman said:
Welcome to PF. :smile:

How is the fixed end supported? Is the full circumference of the metal tube welded to a vertical metal wall? How is the load supported at the far end of the tube? Is there a plate welded to the end and the plate supports the weight of the load?
Essentially I have a metal tube sticking out of a hole of a plastic part. The metal tube is glued inside of the plastic part prior to exiting the hole. This hole has a relatively small clearance between the plastic part and metal tube, therefore I am treating this problem as a cantilever beam problem where the end that is fixed is the point at which the tube exits the metal part.
 
What yield criterion are you using?
 
mechanic667 said:
Essentially I have a metal tube sticking out of a hole of a plastic part. The metal tube is glued inside of the plastic part prior to exiting the hole.
Wouldn't the plastic yield plastically before the metal tube?
 
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Chestermiller said:
What yield criterion are you using?
Van mises for this case

berkeman said:
Wouldn't the plastic yield plastically before the metal tube?
I don't believe so. Essentially what the problem looks like is a a metal tube coming out of a hole in a plastic part, however, once outside the hole there is no plastic material below the metal tube, meaning it can deflect downwards freely if that makes sense. Sorry if that was a little confusing.
 
mechanic667 said:
Essentially what the problem looks like is a a metal tube coming out of a hole in a plastic part, however, once outside the hole there is no plastic material below the metal tube, meaning it can deflect downwards freely if that makes sense.
What are the Young's modulus plots for this plastic (which plastic material is it?) compared to the Young's modulus plot of 304 stainless?
 
The ''beam'' is extremely short compared to how wide/deep it is. The way I see it you will not be able to ignore shear deflection because it will have a significant contribution. Plastic usually has a youngs modulus way lower than any steels so the rotation of the rod in the plastic will also have a part to play. Your deflection, as far as I can tell, will have three components

-shear
-bending
-deformation/rotation of beam in plastic.

The stress in the plastic will be difficult to ignore because it might reach yield before the steel rod does. For the steel you can surely use standard bending and shear deflection equations. The rotation in the plastic is not a simple matter. I am not aware of standard equation for such a case.
 
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You could use this simplified standard approach: $$\sigma_{y}=\frac{M_{y}}{S}=\frac{M_{y}}{\frac{\pi(D^4-d^4)}{32D}}$$ In this case: $$205=\frac{M_{y}}{\frac{\pi(2^4-0.5^4)}{32 \cdot 2}}$$ Thus: ##M_{y}=160.38 \ Nmm##. Now let's find the deflection: $$y=\frac{FL^{3}}{3EI}=\frac{FL^{3}}{3E \frac{\pi(D^4-d^4)}{64}}$$ In this case: $$y=\frac{38.646 \cdot 4.15^{3}}{3 \cdot 190000 \cdot \frac{\pi (2^4-0.5^4)}{64}}=0.00619418 \ mm$$
But this beam has very unusual dimensions so the accuracy of calculations using beam theory might be lower than expected.
 
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