Electric and magnetic field problems (curl/divergence)

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ParoxysmX
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Homework Statement



Consider the electric field E(t,x,y,z) = Acos(ky-wt)k

1. Find a magnetic field such that [itex]\partial_t[/itex]B + [itex]\nabla[/itex] X E = 0
2. Show that [itex]\nabla[/itex] . E = 0 and [itex]\nabla[/itex]. B = 0
3. Find a relationship between k and w that enables these fields to satisfy

[itex]\nabla[/itex] X B = [itex]\mu_{0}[/itex][itex]\epsilon_{0}[/itex][itex]\frac{\partial E}{\partial t}[/itex]

The Attempt at a Solution



Really the problem here is the first one. I understand (sort of) the curl operator, but how do you find [itex]\nabla[/itex] X E? Would you start with a matrix of

[i j k
0 kAcos(ky-wt) 0
0 0 Acos(ky-wt)]

Then find the determinant, which is Acos(ky-wt)(1+k)i - 0j + 0k?
 
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No, that matrix is not correct. The cross product of the del operator [itex]\nabla[/itex] and a vector function is just an alternate convention for denoting curl. You can why here: http://en.wikipedia.org/wiki/Del#Curl. This should also explain why divergence can be denoted: [itex]\nabla \cdot[/itex]

So your matrix should be: [itex]\left[ \begin{array}{ccc}<br /> \hat{i} & \hat{j} & \hat{k} \\<br /> \frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z}\\<br /> 0 & 0 & {\scriptsize A\cos(ky-wt)} \end{array} \right][/itex]

The rest of the problem should be relatively trivial once you know what the operators do.
 
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Ah I see. Thanks for your help.