Electric circuits voltage flow question

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TheRedDevil18
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Homework Statement



circuit.jpg


Homework Equations





The Attempt at a Solution



12.1.1) I don't understand why V2 would have a reading of 12V when V=IR and there is no current flowing in the circuit, can someone please explain?

12.1.2) I think I understand why the voltage is 0 and that is because the resistance in the wires are negligible and voltage is dependent on resistance, Correct?
 
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1) Since there's no current flowing when the switch is open, all resistors can be disregarded. When you redraw the circuit with no resistors, V2's leads will be connected to the anode and cathode of the battery. Therefore, V2 should display a reading of 12V same as V1.

2) Yes, when the switch is closed (short circuit), the reading on V2 should be zero since the wire's resistance is negligible, or in other words, zero. Applying V=IR will result in V= 0.
 
Abstr7ct said:
1) Since there's no current flowing when the switch is open, all resistors can be disregarded. When you redraw the circuit with no resistors, V2's leads will be connected to the anode and cathode of the battery. Therefore, V2 should display a reading of 12V same as V1.

2) Yes, when the switch is closed (short circuit), the reading on V2 should be zero since the wire's resistance is negligible, or in other words, zero. Applying V=IR will result in V= 0.

Ok, that makes sense, Thanks for the explanation