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## Main Question or Discussion Point

We have an electric dipole. Now, let us draw a Gaussian surface around our electric dipole. Now, the total charge enclosed by our Gaussian surface is zero, so according the Gauss' Law the flux through the Gaussian surface is zero, and so is the electric field intensity due the electric dipole.

But, when we apply Coulomb's Law, we get an expression for electric field intensity at a point due to an electric dipole.

So, my question is-

Am I going wrong somewhere in applying the Gauss' theorem?

If not, why are we getting this difference in the solution to this problem?

But, when we apply Coulomb's Law, we get an expression for electric field intensity at a point due to an electric dipole.

So, my question is-

Am I going wrong somewhere in applying the Gauss' theorem?

If not, why are we getting this difference in the solution to this problem?