Electric Dipole Moment question

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SUMMARY

The discussion centers on calculating the magnitude of an electric field exerted on an electric dipole formed by point charges +4.70 and -4.70 separated by 3.90 mm. The torque exerted on the dipole is given as 7.00×10-9 Nm, with the angle between the electric field and the dipole axis specified as 37.0 degrees. The correct calculation using the formula τ = d(sinθ)qE leads to an electric field strength of 634.6 N/C when sin(37) is applied, correcting an earlier miscalculation that incorrectly used sin(30).

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Homework Statement


Point charges +4.70 and -4.70 are separated by distance 3.90mm, forming an electric dipole.
The charges are in a uniform electric field whose direction makes an angle 37.0 degrees with the line connecting the charges. What is the magnitude of this field if the torque exerted on the dipole has magnitude 7.00×10−9 Nm ?

Homework Equations


τ=d(sinθ)qE
E=τ/(sinθ)dq

The Attempt at a Solution


(7E-9) / sin(30)(.0039)(4.7E-9)

763.78 N/C

What am I doing wrong?
 
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Is the angle 30 or 37 degrees?

ehild
 
37, thank you
I was getting so frustrated, stupid error
For anyone else who reads this thread you should get 634.6N/C when you plug in sin(37) into the equation above
 

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