Electric field across a parallel plate capacitor

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SUMMARY

The electric field (E) across a parallel plate capacitor is determined by the configuration of the circuit. In a series circuit with a resistor (R), the electric field is given by E = (V - IR)/L, where V is the potential source and L is the distance between the plates. Once the capacitor is fully charged, the electric field simplifies to E = V/L. Conversely, in a parallel configuration, the electric field remains constant at E = V/L, as all components share the same potential.

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  • Understanding of electric circuits, specifically series and parallel configurations.
  • Knowledge of capacitor charging behavior and time constants.
  • Familiarity with Ohm's Law (V = IR).
  • Basic concepts of electric fields and their relationship to voltage and distance.
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  • Study the behavior of capacitors in RC circuits, focusing on charging and discharging phases.
  • Learn about the implications of series vs. parallel configurations on circuit behavior.
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  • Investigate the mathematical derivation of electric fields in various capacitor configurations.
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johnj7
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Hello,

If I had a potential source (V) , a resistor R, and a parallel plate capacitor,

would the Electric field across the capacitor become

E = (V - IR)/L

L = distance between capacitor

or would the electric field simply become E = V/L

??

thank you!
 
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How is the circuit set up? Your E = (V - IR)/L would be correct for a purely series circuit. But the current would be zero (or quickly become zero as the capacitor charges) so your second formula is then correct.
 
johnj7 said:
Hello,

If I had a potential source (V) , a resistor R, and a parallel plate capacitor,

would the Electric field across the capacitor become

E = (V - IR)/L

L = distance between capacitor

or would the electric field simply become E = V/L

That very much depends on whether the resistor is in series or in || with the capacitor doesn't it?
 
Ah ic, oh okay I understand now.

so if in series,
clearly initially it is

E = (V-IR) /L
but after the capacitor is fully charged then E = V/L

however if in parallel from the start then

E = V/L, always

would this be correct?
 
If the V, R and C are all in parallel then they all have the same potential V.
 

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