Electric Field and charge location

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SUMMARY

The discussion centers on calculating the electric field at a specific location due to a 6.0 mC charge experiencing a force of 2.0 x 10^-3 N. The electric field (E) can be determined using the formula E = F/Q, resulting in an electric field of approximately 333.33 N/C before the charge is placed. Additionally, if the 6.0 mC charge is replaced by a -2.0 mC charge, the force experienced by this new charge can be calculated using the same electric field, demonstrating the principle that the field remains unchanged by the charge itself.

PREREQUISITES
  • Understanding of electric field concepts
  • Familiarity with Coulomb's Law
  • Knowledge of basic physics equations, specifically E = F/Q
  • Ability to manipulate units and perform calculations with microcoulombs (mC)
NEXT STEPS
  • Research the implications of charge interactions in electric fields
  • Learn about the superposition principle in electrostatics
  • Explore the effects of varying charge magnitudes on electric fields
  • Study the relationship between electric fields and forces in different configurations
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism, as well as educators seeking to clarify concepts related to electric fields and charge interactions.

jeremy de leon
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Homework Statement


A 6.0mC charge experiences a force of 2.0x10^-3 N in the +x-direction at a certain point in space.
A. What was the electric field at that location before the charge was placed there
B. What would be the force if the 6mC charge were replaced by a -2.0mC charge?[/B]

Homework Equations


E=F/Q
F=(kQ1Q2)/r^2[/B]

The Attempt at a Solution


I'm actually quite clueless as I think that the given problem lacks information.

I've tried having to use E=F/Q to try and solve for [/B]
 
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jeremy de leon said:
I've tried having to use E=F/Q to try and solve for
... yes, please go on o_O
 
It got cut off, sorry. :)
To solve for the R but it just wouldn't work. So I've got no more ideas for this. I couldn't think of any other solution.
 
jeremy de leon said:
It got cut off, sorry. :)
To solve for the R but it just wouldn't work. So I've got no more ideas for this. I couldn't think of any other solution.
You don't need R to find the field. You were on the right track with E = F/Q.
 
Yeah I got the electric field but how do i get the electric field BEFORE the charge was placed there?

Sorry, this is really confusing me. :/
 
The value that you got will be the field before the new charge is placed. The new charge reacts to the field that is due to other charges, not to its own field. Of course, if another charge were to be brought into the picture, then the new charge would feel the effects of the previous field plus the that of the field due to the original Q, and Q would also feel the new charge.
 

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