Hey there, im new to this site and was wondering if anyone could help me with a problem I'm stuck on: The electric potential is given at the four corners of a 1 cm square: V1 = 1.6 V, V2 = 12.4 V, V3 = 1.6 V, V4 = -9.2 V. What is the magnitude of the electric field at the centre of the square? This seems like it should be easy, but for some reason I just can't get it. Attempt: Ok, I know that E=deltaV/r and V=kq/r and E= kq/r^2 I've tried finding the differences in the voltage, V1-v2, v2-v3, v3-v4 and v4-v1. then i could find the electric field at that point. Since the voltages arent the same, then the electric field at the center isnt zero. I'm just really stuck and think that I'm making it harder than it really is. I also know that the sum of the potential differences around a closed path are equal to zero, but im not sure if this would help me. Help?