Electric Field and Electric Potential

Click For Summary
SUMMARY

The discussion centers on the electric field and electric potential of a uniformly charged sphere with radius R and charge Q. For points inside the sphere (r < R), the electric field E is 0 and the potential V is kQ/R, making the correct answer A. For points outside the sphere (r > R), the electric field E is kQ/(r^2) and the potential V is kQ/r, confirming answer D as correct. The integration of the electric field to find potential is emphasized, clarifying the relationship between E and V.

PREREQUISITES
  • Understanding of electric fields and potentials
  • Familiarity with Coulomb's law and the constant k
  • Knowledge of integration in physics
  • Concept of uniform charge distribution on a sphere
NEXT STEPS
  • Study the principles of electrostatics and electric fields
  • Explore the concept of electric potential and its mathematical derivation
  • Learn about Gauss's law and its applications in electrostatics
  • Investigate the effects of charge distribution on electric fields
USEFUL FOR

Physics students, educators, and professionals in electrical engineering seeking to deepen their understanding of electrostatics and the behavior of electric fields and potentials around charged objects.

Dorney
Messages
15
Reaction score
0
[SOLVED] Electric Field and Electric Potential

1. Refer to a sphere of radius R that has a positive charge Q uniformly distributed on its surface.

Which of the fllowing represents the magnitude of the electric field E and the potential V as functions of r, the distance from the center of the sphere, where r < R?

A) E = 0 and V = kQ/R
B) E = 0 and V = kQ/r
C) E = 0 and V = 0
D) E = kQ/(r^2) and V = 0
E) E = kQ/(R^2) and V = 0


Which of the following represents the magnitude of the electirc field E and the potential V as functions of r, the distance from the center of the sphere, where r > R?

A) E = kQ/(R^2) and V = kQ/R
B) E = kQ/R and V = kQ/R
C) E = kQ/R and V = kQ/r
D) E = kQ/(r^2) and V = kQ/r
E) E = kQ/(r^2) and V = kQ/(r^2)


2. E = kq/(r^2) and V = kq/r


3. Thinking it through, I got the answers B and D, respectively.

Thanks in advance!
 
Physics news on Phys.org
nm i got it.
 


Is the answer actually B and D?

I'm thinking it might be C and D. Potential is the integration of the electric field dotted with dr. If E is zero, how can there be any potential? Am I wrong?
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
1K
Replies
5
Views
609
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K