Electric Field and spherical cavities

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SUMMARY

The discussion focuses on the electric field and surface charge distribution in a neutral conducting sphere with two spherical cavities containing point charges qa and qb. The surface charge densities are derived using Gauss's law, leading to the equations for surface charges σa, σb, and σR. It is established that the surface charge must be negative, as it opposes the positive point charges at the centers of the cavities, ensuring the total charge within a Gaussian surface remains zero.

PREREQUISITES
  • Understanding of Gauss's Law in electrostatics
  • Familiarity with electric fields and potential concepts
  • Knowledge of surface charge density calculations
  • Basic principles of conductors in electrostatic equilibrium
NEXT STEPS
  • Study the derivation of electric fields using Gauss's Law
  • Learn about the behavior of conductors in electrostatic equilibrium
  • Explore the concept of electric potential and its relationship to electric fields
  • Investigate the effects of multiple point charges on electric fields
USEFUL FOR

This discussion is beneficial for physics students, electrical engineers, and anyone studying electrostatics, particularly those interested in charge distributions in conductors.

stunner5000pt
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Two spherical cavities of radii a and b are hollowed out from the interior of a neutral conducting sphere of radius R. At the center of each cavity is a point charge place, callthem qa and qb

a) Find the surface charges sigma a, sigma b, and sigma R.

ok say for qa

[tex]\vec{E} = \frac{q_{a}}{4 \pi \epsilon_{0} a^2} \hat{a} = - \vec{\nabla} V \bullet \hat{n}[/tex]

also [tex]\sigma = -\epsilon_{0} \vec{\nabla} V \bullet \hat{n} = \frac{q_{a}}{4 \pi a^2}[/tex]

but i was told this answer should be negative.. where is my mistake?
 

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The total charge inside a guassian surface surrounding one inner sphere has to be zero, The surface charge must have the opposite sign of the central charge.
 

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