Electric field and the charged conductor.

Click For Summary
Under electrostatic conditions, a neutral conductor placed in an external electric field encloses a net zero electric field within it. In contrast, the electric field within a charged conductor subjected to an external electric field is non-zero, as stated by a professor. However, if this were true, it would cause free electrons to remain in motion, preventing electrostatic conditions from being established. Therefore, the interior of an ideal conductor remains charge-free, and the steady-state electric field inside any conductor is zero when no current flows. The only electric field present inside a conductor occurs when there is current, described by the relationship between current density and conductivity.
rohit dutta
Messages
19
Reaction score
0
It is well known that under electrostatic conditions, a neutral conductor when placed in an external electric field encloses a net zero electric field within it. But, do you think that the electric field within a charged conductor is zero, when it is placed in an external electric field?

According to a professor, the net electric field within a charged conductor is non-zero in this case. Do textbooks also say this?

Well, if it were true, then the net electric field within would keep the free electrons in motion and electrostatic conditions will never be achieved.
 
Physics news on Phys.org
rohit dutta said:
But, do you think that the electric field within a charged conductor is zero, when it is placed in an external electric field?
Yes it is.

Well, if it were true, then the net electric field within would keep the free electrons in motion and electrostatic conditions will never be achieved.
That's exactly the reason why the interior of an ideal conductor is always charge-free.
 
For zero current flowing, the steady-state E field inside any conductor is zero. That's so for any conductivity > 0.

The only E field existing inside a conductor is if there is current and is given by j = σ E, j = current density, σ = conductivity. (Certain crystalline and anisotropic materials do not follow this exact equation).
 
(a) The polarisation pattern is elliptical with maximum (1,1) and minimum (-1,-1), and anticlockwise in direction. (b) I know the solution is a quarter-wave plate oriented π/4, and half-wave plate at π/16, but don't understand how to reach there. I've obtained the polarisation vector (cos π/8, isin π/8) so far. I can't find much online guidance or textbook material working through this topic, so I'd appreciate any help I can get. Also, if anyone could let me know where I can get more...

Similar threads

  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
2
Views
2K
Replies
10
Views
2K
Replies
4
Views
4K
Replies
2
Views
2K
Replies
2
Views
4K
Replies
9
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K