Electric Field and total energy

  • Thread starter SamTsui86
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  • #1
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Homework Statement



Two point charges lie along the y axis. A charge of q1 = -12.0 µC is at y = 7.0 m, and a charge of q2 = -2.0 µC is at y = -4.0 m. Locate the point (other than infinity) at which the total electric field is zero.

Homework Equations



E = (K lql) / r^2


The Attempt at a Solution



I setup the two equation make E = 0
so

(K lq1l) / (7-y)^2 = (K lq2l) / (-4+y)^2

It's wrong, plz correct my equation
 

Answers and Replies

  • #2
Pyrrhus
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Why do you think that equation is wrong?
 
  • #3
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I think the equation is wrong because I double checked all my math and it said that the answer is wrong.
 
  • #4
Pyrrhus
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Ok, Let's review again:

The point in which the electric field will be 0 is between the charges. Because of the standard convention. You picked a point inside so it's correct.

Next we have to set our electric field vectors, such that:

[tex] \vec{E}_{1} + \vec{E}_{2} = \vec{0} [/tex]

[tex] \vec{E}_{1} = K \frac{|q_{1}|}{(7-y)^{2}} \vec{j} [/tex]

[tex] \vec{E}_{2} = -K \frac{|q_{1}|}{(4+y)^{2}} \vec{j} [/tex]

so, the error was using -4, because r will be a distance.
 
Last edited:

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