Electric field between parallel plates

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Homework Help Overview

The discussion revolves around the electric field between parallel plates, specifically in the context of conducting plates and capacitors. Participants are exploring the behavior of electric fields in static situations and the implications of charge distribution on the plates.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants are questioning whether both surfaces of a conducting plate are charged and what determines the charge distribution. There is also a discussion on the application of the superposition principle to determine the electric field between and outside the plates of a capacitor.

Discussion Status

The discussion is ongoing with various questions being raised about charge distribution and the nature of electric fields in different configurations. Some participants are providing links to external resources, indicating an exploration of related concepts.

Contextual Notes

There are references to the fringing effects of finite parallel-plate capacitors and a note that the error in an earlier post is considered fundamental, suggesting a deeper issue in the understanding of the topic.

lys04
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Homework Statement
The electric field outside a conducting plate of charge is given by sigma/epsilon right? Then why not for a capacitor, since that is 2 conducting plates, is the electric field 2sigma/epsilon using superposition principle?
Relevant Equations
E=sigma/epsilon
^^
 
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Here’s a cross -section through (due to space limitations, part of) an infinite conducting plate with a (say) positive charge:
___________________________
___________________________

Here are some questions to consider:
- are both surfaces charged?
- if only one (of the two) surfaces is charged, what determines which one?
- in a static situation, every ‘field line’ starts on a positive charge and ends on a negative charge; where are the negative charges here?
 
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lys04 said:
Homework Statement: The electric field outside a conducting plate of charge is given by sigma/epsilon right? Then why not for a capacitor, since that is 2 conducting plates, is the electric field 2sigma/epsilon using superposition principle?
Relevant Equations: E=sigma/epsilon
Generally, the two plates of a capacitor are oppositely charged. Right?

So, if one plate has a surface charge density, ##\sigma##, then the other plate has surface charge density, ##-
\sigma##,

Now use superposition to determine the electric field outside the plates as well as between the plates.
 
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