Electric Field Between Two Disks

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Homework Help Overview

The problem involves calculating the electric field at the midpoint between two charged disks, one negatively charged and the other positively charged. The disks are specified to be 10 cm in diameter and are positioned 29 cm apart, with given charges of -50 nC and +50 nC.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the application of the electric field formula for a disk and question the validity of the formula being used. There is mention of attempting to double the calculated value to account for both disks and seeking confirmation from others on their methods.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the formula for the electric field of a disk. Some have expressed uncertainty about the formula's accuracy and its application in this context. There is no explicit consensus yet, but participants are engaging in clarifying their approaches.

Contextual Notes

Participants note discrepancies between the formula they are using and other sources, suggesting potential confusion stemming from differing educational materials. The original poster expresses frustration regarding the alignment of homework resources with in-class instruction.

k8thegr8
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Homework Statement



Two 10-cm-diameter charged disks face each other, 29cm apart. The left disk is charged to -50 nC and the right disk is charged to +50 nC. What is the magnitude of the electric field E⃗ at the midpoint between the two disks?

The answer is 3.9 x 104 N/C


Homework Equations



Edisk = (KQ/R2)[1 - z/√(z2 + R2)]
Where
Q = Charge of the disk in Coulombs = 5 x 10-8 C
R = Radius of the disk in meters = 0.05m
Z = Distance from the disk in meters = 0.145m


The Attempt at a Solution



This seems like a simple plug-and-chug to me. I've tried using the Electric Field of a Disk formula above and I've tried doubling my answer to accommodate for the two plates. Can anyone else hit that magic number, and if so, how did you do it? I'd like to know for an exam coming up.

Thanks!
 
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Don't forget that you have two disks that are separated (by 29 cm)!
 
k8thegr8 said:

Homework Statement



Two 10-cm-diameter charged disks face each other, 29cm apart. The left disk is charged to -50 nC and the right disk is charged to +50 nC. What is the magnitude of the electric field E⃗ at the midpoint between the two disks?

The answer is 3.9 x 104 N/C


Homework Equations



Edisk = (KQ/R2)[1 - z/√(z2 + R2)]
Where
Q = Charge of the disk in Coulombs = 5 x 10-8 C
R = Radius of the disk in meters = 0.05m
Z = Distance from the disk in meters = 0.145m


The Attempt at a Solution



This seems like a simple plug-and-chug to me. I've tried using the Electric Field of a Disk formula above and I've tried doubling my answer to accommodate for the two plates. Can anyone else hit that magic number, and if so, how did you do it? I'd like to know for an exam coming up.

Thanks!
Are you sure about your formula for Edisk?
 
vela said:
Are you sure about your formula for Edisk?

You know, I'm beginning to think that my problem lies there. As I look around the internet, it seems like everyone has their own personal formula for Edisk, such as this website which essentially multiplies my formula by 2.

Now that's not to say I'm not peeved that my professor picked a homework website that didn't jive with his in-class notes, but that's a separate issue.
 

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