Electric field calculation part B

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Lewis
I'm having trouble with the question included in the attachment, part B specifically. If anyone could start me off it would be a great help!

Also, my answer for part A is included if anyone would care to check it o:)
-Note: Chances are it's wrong :smile:​
 
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  • Textbook problem 34 with a diagram of a cylinder of length h and radius R, a thin slice of width dx, and point at distance d; handwritten answer A shows -k_e times a bracket of two terms 1 over square root of (2d+h)^2+R^2 minus 1 over square root of (2d)^2+R^2.
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Lewis said:
I'm having trouble with the question included in the attachment, part B specifically. If anyone could start me off it would be a great help!

Also, my answer for part A is included if anyone would care to check it o:)
-Note: Chances are it's wrong :smile:​
I can't open your attachment. Why don't you cut and paste and put it in without the attachment?
 
I also get your answer to (A), with \lambda=Q/h.
I think the easiest way to do (B) is:
1. Use the field of a ring to get the field a distance z from a disk of charge Q. Use dq=2pi r dr/(pi r^2 Q) and integrate r from 0 to R.
This should give E=(2Q/R^2)[1-z/sqrt{z^2+R^2}].
2. Integrate E for the disk the same way you must have done for E for the ring for the hollow cylinder.
Let me know if you want to know the answer.