Electric Field Distribution of a disk

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SUMMARY

The discussion focuses on calculating the electric field (E) at a point P located 10 cm above the center of a thin disc with a central hole. The disc has a radius of 60 cm and a hole of radius 30 cm, with a total charge of 10^-3 C uniformly distributed over its surface. Participants discuss the setup of the differential charge element (dq) using the formula dq = σ2πrdr, where σ represents the surface charge density derived from the total surface area of the disc.

PREREQUISITES
  • Understanding of electric field concepts and calculations
  • Familiarity with surface charge density (σ) and its calculation
  • Knowledge of integration techniques for continuous charge distributions
  • Basic physics of electron motion in electric fields
NEXT STEPS
  • Calculate the total surface area of the disc to determine the surface charge density (σ)
  • Learn about the integration of electric fields from continuous charge distributions
  • Explore the concept of electric field lines and their symmetry in charge distributions
  • Investigate the motion of charged particles in electric fields, specifically for electrons
USEFUL FOR

Physics students, electrical engineers, and anyone interested in electrostatics and electric field calculations.

davidflip
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Hi can someone help me with this problem?

A thin disc of radius 60 cm has a hole its center of radius 30 cm. A total charge of
10^-3C is distributed uniformly on its surface. Find E at a point P which is 10 cm. on the central axis of this disc.
What would be the acceleration of an electron passing through point P ?. Mass of electron = 9.11*10^-31 Kg.

How would I set up dq for this?
would it simply be dq= σ2∏rdr? and if it is what is the numerical value for σ?

Thank you!
 
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You have a uniform charge distribution. Can you calculate the total surface area of your disk? This should give you σ.

would it simply be dq= σ2∏rdr?
If you use the symmetry of the setup, you can use that.
 

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