Electric Field Distribution of a disk

  • Thread starter davidflip
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  • #1
davidflip
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Hi can someone help me with this problem?

A thin disc of radius 60 cm has a hole its center of radius 30 cm. A total charge of
10^-3C is distributed uniformly on its surface. Find E at a point P which is 10 cm. on the central axis of this disc.
What would be the acceleration of an electron passing through point P ?. Mass of electron = 9.11*10^-31 Kg.

How would I set up dq for this?
would it simply be dq= σ2∏rdr? and if it is what is the numerical value for σ?

Thank you!!
 

Answers and Replies

  • #2
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You have a uniform charge distribution. Can you calculate the total surface area of your disk? This should give you σ.

would it simply be dq= σ2∏rdr?
If you use the symmetry of the setup, you can use that.
 

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