Electric Field magnitude and distance

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SUMMARY

The discussion centers on calculating the electric field magnitude of a radon nucleus at a distance of 6.0 x 10-10 m. The total charge of the radon nucleus is established as 1.38 x 10-17 C. The formula used for the electric field is E = kq/r2, where k is Coulomb's constant (8.99 x 109 N m2/C2). The correct calculation yields an electric field magnitude of 2.07 x 1012 N/C, confirming the method's validity after correcting minor mathematical errors.

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Homework Statement


The first question that was asked was; What is the total charge of the radon nucleus? (The neutral radon atom has 86 electrons.)
the answer to that is 1.38*10^(-17) C
the second question asked is;
What is the magnitude of its electric field at a distance of 6.0 x10-(10) m from the nucleus?


Homework Equations


E=kq/r^2

The Attempt at a Solution



I tried using the equation E=kq/r^2
E=(8.99*10^9)*(1.38*10^(-17)/((6.0*10^(-10)^2))=2.07*10^(12) N/C
but this answer isn't right? I'm not sure why its not right as this is the only method I know how to do in order to solve this problem.
If someone could please show me what it is I'm doing wrong I'd really appreciate it :)
 
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Your method looks okay, but your math could use another look.
 
Got the right answer!
I'm not sure what I did wrong with my math there but it worked out after!
Thanks for pointing that out !
 

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