Electric field of a cylinderical insulator

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SUMMARY

The discussion focuses on calculating the electric field of a long cylindrical insulator with a uniform charge density of 1.79 µC/m and a radius of 3 cm. Using Gauss' Law, the electric field inside the insulator at a distance of 2 cm is determined, while the electric field at 10 cm is also calculated. The key takeaway is the application of Gauss' Law, specifically the integral form ∫ E • dA = Q_enclosed / ε₀, to derive the electric field values based on the given parameters.

PREREQUISITES
  • Understanding of Gauss' Law in electrostatics
  • Familiarity with cylindrical coordinate systems
  • Knowledge of electric field concepts and calculations
  • Basic proficiency in calculus for integration
NEXT STEPS
  • Study the derivation of electric fields using Gauss' Law in different geometries
  • Explore the concept of charge density and its impact on electric fields
  • Learn about the properties of cylindrical conductors and insulators
  • Investigate the applications of electric fields in real-world scenarios
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Students studying electromagnetism, physics educators, and anyone interested in understanding electric fields in cylindrical geometries.

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Homework Statement


A long cylindrical insulator has a uniform charge density of 1.79 µC/m and a radius of 3 cm. What is the electric field inside the insultor at a distance of (a) 2 cm? [Answer in units of N/C] (b) 10 cm.

Homework Equations


∫ E • dA = Q_enclosed / e_0

The Attempt at a Solution


I know I have to use Gauss’ Law by constructing a cylindrical Gaussian surface of radius r (r<R) and length l. However, I can't seem to figure out how to get the height to cancel out since it isn't given in the question.
 
Last edited:
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I figured out part a, but I'm still stuck on b.
 
Figured out part b.
 

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