Electric Field, Potential, and Work at a Point

Click For Summary
SUMMARY

The discussion centers on calculating electric fields, potentials, and work at a specific point in a system of charges. The electric field is derived using the formula E = kq/r², leading to a resultant field of +ek/a². The potential V is calculated using V = -Ea, where 'a' is the distance from the charge. Work done W is determined using W = -Vq, where 'q' is the total charge. The importance of vector direction in electric field calculations and the relationship between potential and work is emphasized.

PREREQUISITES
  • Understanding of electric field intensity and vector components
  • Familiarity with the equations E = kq/r², V = -∫ E ⋅ ds, and W = -Vq
  • Knowledge of scalar and vector quantities in physics
  • Basic concepts of charge interactions and potential energy
NEXT STEPS
  • Study the concept of electric field vectors and their directional components
  • Learn about the relationship between electric potential and work done in electrostatics
  • Explore the implications of charge configurations on electric field calculations
  • Investigate the conditions under which charges remain bound or separate in electric fields
USEFUL FOR

Students and educators in physics, particularly those focusing on electromagnetism, as well as anyone involved in solving problems related to electric fields, potentials, and work in electrostatic systems.

Adeel Ahmad
Messages
45
Reaction score
0

Homework Statement


upload_2016-5-7_12-5-20.png

upload_2016-5-7_12-5-50.png


Homework Equations


E = kq/r2
V = -∫ E ⋅ ds
W = -Vq

The Attempt at a Solution


a) I just summed up the electric fields: +ek/a2 +ek/a2 -ek/a2 so I get +ek/a2 as a result. Not sure if this is correct since -e has a y component so I was thinking to use sin but not sure which angle to use.

b) i would just plug in the electric field from part a and plug in a as the distance, so V = -Ea

c) W = -Vq, get the potential from b and for q get the sum of charges. Not sure if that's a correct approach.

d) I'm not sure what equation to use for this.
 
Physics news on Phys.org
Adeel Ahmad said:
a) I just summed up the electric fields: +ek/a2 +ek/a2 -ek/a2 so I get +ek/a2 as a result. Not sure if this is correct since -e has a y component so I was thinking to use sin but not sure which angle to use.

b) i would just plug in the electric field from part a and plug in a as the distance, so V = -Ea

c) W = -Vq, get the potential from b and for q get the sum of charges. Not sure if that's a correct approach.

d) I'm not sure what equation to use for this.

a. electric field intensity is a vector - so you must put in the direction of the fields at P due to charges -use the symmetry of the figure;
as your charges -e are equidistant from the point p. so get a correct value of the field at P

b. if you know the field you can also calculate the potential due to the charges -these are scalars therefore it will be added
c. what is the condition that charges will be bound or fly apart?
d. calculate the work done in bringing an unit positive charge from infinity to the point p -is it related to potential at that point.?
can work done by the field related to speed of the particle ?
some questions are to develop one'concept about charges and fields.
 
  • Like
Likes   Reactions: Adeel Ahmad

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 7 ·
Replies
7
Views
896
  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
1
Views
2K
Replies
1
Views
2K
Replies
10
Views
2K
  • · Replies 11 ·
Replies
11
Views
1K