Electric Field Strength at Point Z

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Homework Help Overview

The discussion revolves around calculating the electric field strength at a specific point (Point Z) due to two charged spheres, one negatively charged and the other positively charged. The problem involves understanding the contributions of each charge to the electric field at Point Z and the resulting direction of the field.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of electric field strengths from two charges and the vector sum of these fields. Questions arise about the correctness of the calculations and the implications of charge movement in electric fields.

Discussion Status

Participants have shared their calculations and results, with some expressing agreement on the methodology. Additional questions about the behavior of charges in electric fields and related concepts are being explored, indicating an ongoing dialogue without a definitive conclusion.

Contextual Notes

There is a mention of a related question regarding the movement of a charged test particle in an electric field, as well as a reference to a scenario involving charges in a magnetic field. The original problem does not specify the nature of the test charge, which adds to the complexity of the discussion.

pinkyjoshi65
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what are the magnitude and direction of the electrical field strength at point Z in the situation below?
negatively charged sphere, x(-2.0*10-5C) is left most, 60 cm to the right of it is a positively charged sphere,Y (8.0*10-6C). Point Z is 30 cm to the right of Y.

What I did:
First i found E1, where q1= -2*10-5 C and r= 0.90 m (direction is right)

Then I found E2, where q2= 8.0*10-6 C and r= 0.30m (direction is left)
then i found the vector sum of E1 and E2, and found the field strenth at Z (direction is Left)

Is this right??
 
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Seems right, what is your final answer?
 
final answer is 577800 N/C (left)
 
got another question--not a problem..if a stationary charged test particle is free to move in an electrical field, in what direction will it begin to move?
 
Anyone..??
 
That depends on the direction of the field and the nature of the test charge. Typically, a "test" charge is a positive and will be accelerated in the same direction as the field.
 
ah..k..i see..i saw in one of the websites, that the charge moves in a circular direction..
 
pinkyjoshi65 said:
ah..k..i see..i saw in one of the websites, that the charge moves in a circular direction..

Was this a charge in a magnetic field?
 
Last edited by a moderator:
  • #10
The simulation I see when I click that link shows both an electric and magnetic field. The charged particle in question also has an initial velocity...Unless you are setting the parameters to some other situation...
 
  • #11
k i guess then ur right..one more question:three small, negatively charged spheres are located at the vertices of an equilateral triangle.The magnitudes of the charges are equal. Sketch the electical field in the region around this charge distribution, including the space inside the triangle.

ok..so all i know is that density of field lines will be more whr the field is greater..
 

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