Electric field strength from a light bulb

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 10K views
A90
Messages
4
Reaction score
0

Homework Statement


What is the approximate electric field strength of the electromagnetic waves radiated by a 100-W light bulb, measured 3.0m from the bulb?

Homework Equations


$$\vec{E}=\frac{kq}{d^{2}}$$

$$P=\frac{2kq^{2}a^{2}}{3c^{3}}$$

The Attempt at a Solution


I solved for ##q=\sqrt{\frac{3Pc^{3}}{2ka^{2}}}##, and then plugged that into the equation for electric field, and I have all the values I need to solve except for the acceleration, which I'm not sure how to find. I thought about using the second derivative of ##x(t)= x~sin(\omega~t)##, but I don't know what to use for ##x##, ##\omega## or ##t##.
 
Last edited by a moderator:
Physics news on Phys.org
Your model assumes that lightbulb filaments produce light by having a monopole charge ##q## that radiates energy. That's not how light bulbs work. For this calculation, you need to consider the flux of electromagnetic energy through a sphere of radius 3.0 m and relate that flux to the amplitude of the electric field in the electromagnetic plane wave that crosses the sphere.

Edited to correct typo.
 
Last edited:
Reply
  • Like
Likes   Reactions: tech99