Electric field strength from x=-a to x = a

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 1K views
physiccool78
Messages
8
Reaction score
0

Homework Statement


I attached a file.

Numbers 10 and 12.

Homework Equations



kQq/r, kQq/r^2

The Attempt at a Solution



I am confused about this problem. Shouldn't the electric field strength be 0 when x = 0? The charges are opposite and adding two opposite vectors with equal magnitude should be 0 right? So how come the answer says that the electric field strength is the greatest at x = 0 then? Thank you.
 

Attachments

  • photo 1.JPG
    photo 1.JPG
    29.2 KB · Views: 468
  • photo 2.JPG
    photo 2.JPG
    35.8 KB · Views: 477
Physics news on Phys.org
They are in opposite positions on the y axis,so the vectors of the electric fields point in the same direction.They both point to the negative charge.
 
Wow... Thank you and now I feel embarrassed for asking this question! I can't believe I overlooked this. Thank you.
 
Just be a little more patient with physics problems,however simple or confusing they might be.