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Electric field strength from x=-a to x = a

  1. Sep 7, 2015 #1
    1. The problem statement, all variables and given/known data
    I attached a file.

    Numbers 10 and 12.

    2. Relevant equations

    kQq/r, kQq/r^2

    3. The attempt at a solution

    I am confused about this problem. Shouldn't the electric field strength be 0 when x = 0? The charges are opposite and adding two opposite vectors with equal magnitude should be 0 right? So how come the answer says that the electric field strength is the greatest at x = 0 then? Thank you.
     

    Attached Files:

  2. jcsd
  3. Sep 7, 2015 #2
    They are in opposite positions on the y axis,so the vectors of the electric fields point in the same direction.They both point to the negative charge.
     
  4. Sep 7, 2015 #3
    Wow... Thank you and now I feel embarrassed for asking this question! I can't believe I overlooked this. Thank you.
     
  5. Sep 7, 2015 #4
    Just be a little more patient with physics problems,however simple or confusing they might be.
     
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