(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

2 point charges are situated 45nm apart in a vacuum. Charge A is +8μC and charge B is -25μC. X is a point 8nm from A.

Calculate the electric field strength at point X only due to A (Ans is 1.2 x 10^9 N/C)

Calculate the overall electric field strength at point X due to A and B. (Ans is 1.32 x 10^9 N/C)

2. Relevant equations

E = [itex]\frac{1}{4\pi\epsilon}[/itex] X [itex]\frac{Q}{d^{2}}[/itex]

3. The attempt at a solution

Electric field strength due to A.

[itex]\frac{1}{4\pi(8.9X10^-12)}[/itex] X [itex]\frac{8X10^-6}{(8X10^-9)^{2}}[/itex]

= 1.117X10^21

= 1.12X10^21 N/C

Electric Field Strength due to B.

E = [itex]\frac{1}{4\pi(8.9X10^-12)}[/itex] X [itex]\frac{25X10^-6}{(37X10^9)^{2}}[/itex]

= 1.632X10^20

= 1.63X10^20 N/C

1.12X10^21 + 1.63X0^20 = 1.283X10^21 N/C

Where am I going wrong?

I would appreciate any help.

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# Homework Help: Electric Field Strength problem.

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