Electric field with three charges

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SUMMARY

The discussion focuses on calculating the electric field generated by three charges: q1 = +4.07 μC, q2 = +4.07 μC, and q3 = -4.07 μC, arranged at the vertices of an equilateral triangle with a side length of d = 2.29 cm. The key insight is that the electric fields E1 and E2 from q1 and q2 cancel each other out at the midpoint between them, allowing the electric field at that point to be determined solely by q3. The participants emphasize the importance of calculating the x and y components of E3, utilizing the angle of 30 degrees to split the components effectively.

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  • Knowledge of vector decomposition in two dimensions
  • Familiarity with equilateral triangle properties
  • Ability to perform calculations involving microcoulombs (μC) and centimeters (cm)
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FlipStyle1308
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Here is the problem which I need to solve:

The following picture shows a system consisting of three charges, q1 = +4.07 μC, q2 = +4.07 μC, and q3 = -4.07 μC, at the vertices of an equilateral triangle of side d = 2.29 cm. Find the magnitude of the electric field at a point halfway between the charges q1 and q2. Also find the magnitude of the electric field at the point halfway between the charges q2 and q3.

19-32.gif


I pretty much already got down that I have to use x and y components, and got that E1 and E2 cancel each other out (using the equation E = q/r^2). I just pretty much need to figure out how to get the x and y components for E3, and I think I'll be able to finish up the problem on my own. Thanks.
 
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FlipStyle1308 said:
I pretty much already got down that I have to use x and y components, and got that E1 and E2 cancel each other out (using the equation E = q/r^2). I just pretty much need to figure out how to get the x and y components for E3, and I think I'll be able to finish up the problem on my own. Thanks.

Yeah, you're right on track. Can you figure out the angle so that you can split E3 into x & y components? (Hint: You know it's an equilateral triangle)
 
Last edited:
This is one thing I was stuck at...60 degrees or 30 degrees (to cut the angle in half to go directly in between E2 and E3)? I'm leaning toward 30 degrees, am I right?
 
Hi flipstyle,
you have an equilateral triangle, so if you trace a line which joint q3 and the midpoint between q1 q2, the lengh of this segment will be d√3/2.
A test charge placed at halfway between q1 and q2 will be affected only by q3 since the influence of q1 and q2 cancel each other. So the electric field will be along the line joining the midpoint and q3.
 
a test charge halfway between q2 and q3,call this point M, will experience a repulsion from q2, attraction from q3 with the same intensity. so the electric field at M will have a component along the line joining M and q3.

But the same test charge at M will also experience a repulsion from q1 that you can calculate the same maner as you have done for the first question. This repulsive force will be along the line q1 M.
This gives you to perpendicular component of the electric force at M.
From this it should be easy for you to continue.
Bye
 
Thanks for all the help/tips...I figured it out.
 
Last edited:

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