Electric Fields involving Disks

I think that the last statement is also correct. What do you think?No...I think that the last statement is also correct. What do you think?Oh, yes, the net electric field at the location of the chloride ion is zero. So that statement is also correct.
  • #1
demonhunter19
10
0

Homework Statement


A thin circular sheet of glass of diameter 6 meters is rubbed with a cloth on one surface, and becomes charged uniformly. A chloride ion (a chlorine atom which has gained one extra electron) passes near the glass sheet. When the chloride ion is near the center of the sheet, at a location 0.5 mm from the sheet, it experiences an electric force of 8e-15 N, toward the glass sheet.
It will be useful to you to draw a diagram on paper, showing field vectors, force vectors, and charges, before answering the following questions about this situation.

Which of the following statements about this situation are correct? Select all that apply.

  • The charged disk is the source of the electric field that causes the force on the chloride ion.

    The force on the chloride ion is equal to the electric field of the glass sheet.

    The electric field that acts on the chloride ion is due to the charge on the glass sheet and to the charge on the chloride ion.

    The electric field of the glass sheet is equal to the electric field of the chloride ion.
    The net electric field at the location of the chloride ion is zero.

Homework Equations


Electric Field of a Disk:
e15-8.jpg

Electric FORCE due to some charge: F=qE

The Attempt at a Solution


I'm not sure which statement is correct, but it seems like the first three (The charged disk is the source of the electric field that causes the force on the chloride ion. The force on the chloride ion is equal to the electric field of the glass sheet. The electric field that acts on the chloride ion is due to the charge on the glass sheet and to the charge on the chloride ion) are correct.

I know the electric force exerted on the Chlorine atom, which is 8e-15N, and I set it equal to (-1.6e-19)(Q/(6^2*pi))/2*ε), which is really the relative equation between the electric force and the electric field, F=qE, q being the charge.

The answer I got for Q (the charge of the disk, which is what the 2nd part of the question is asking) is -.000025C. I'm not sure if it's right, but given the relative size of the disk, it makes sense.

And I'm still not certain about which statements above are correct (1st part of question)
 
Last edited:
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  • #2
Welcome to PF demonhunter19,

demonhunter19 said:
I'm not sure which statement is correct, but it seems like the first three (The charged disk is the source of the electric field that causes the force on the chloride ion. The force on the chloride ion is equal to the electric field of the glass sheet. The electric field that acts on the chloride ion is due to the charge on the glass sheet and to the charge on the chloride ion) are correct.

I know the electric force exerted on the Chlorine atom, which is 8e-15N, and I set it equal to (-1.6e-19)(Q/(6^2*pi))/2*ε), which is really the relative equation between the electric force and the electric field, F=qE, q being the charge.

The answer I got for Q (the charge of the disk, which is what the 2nd part of the question is asking) is -.000025C. I'm not sure if it's right, but given the relative size of the disk, it makes sense.

And I'm still not certain about which statements above are correct (1st part of question)
Let's take a look at the first three statements then:
demonhunter19 said:
The charged disk is the source of the electric field that causes the force on the chloride ion.
I agree :approve:
demonhunter19 said:
The force on the chloride ion is equal to the electric field of the glass sheet.
What are the units of force? What are the units of the electric field?
demonhunter19 said:
The electric field that acts on the chloride ion is due to the charge on the glass sheet and to the charge on the chloride ion.
Suppose we have a completely empty region of space, devoid of any matter, energy or fields. Suppose then we place a single point charge in this region. Would this create an electric field in the region?
 
  • #3
Hootenanny said:
Welcome to PF demonhunter19,Let's take a look at the first three statements then:

I agree :approve:

What are the units of force? What are the units of the electric field?

Suppose we have a completely empty region of space, devoid of any matter, energy or fields. Suppose then we place a single point charge in this region. Would this create an electric field in the region?
Right, the 2nd statement cannot be true, since Force is in Newtons, whilst the electric field is in Newtons/Coulombs. As for the 3rd statement, I'm not entirely sure, but I would imagine that at any time or space, there will always be an electric field created by a charge.
 
  • #4
demonhunter19 said:
Right, the 2nd statement cannot be true, since Force is in Newtons, whilst the electric field is in Newtons/Coulombs.
Correct :approve:
demonhunter19 said:
As for the 3rd statement, I'm not entirely sure, but I would imagine that at any time or space, there will always be an electric field created by a charge.
Again correct, does this electric field act on the point charge itself?
 
  • #5
Hootenanny said:
Correct :approve:

Again correct, does this electric field act on the point charge itself?
I don't think so. It would also act on other objects (assuming that there are other objects within that electric field).
 
  • #6
demonhunter19 said:
I don't think so. It would also act on other objects (assuming that there are other objects within that electric field).
Correct :approve:. So how can the field that acts on the chloride ion be due to the chloride ion?
 
  • #7
Hootenanny said:
Correct :approve:. So how can the field that acts on the chloride ion be due to the chloride ion?
Ah, now I see the mistake! Thanks. So the only statement that is correct out of the 5 is the first one.
 
  • #8
demonhunter19 said:
Ah, now I see the mistake! Thanks. So the only statement that is correct out of the 5 is the first one.
No problem, sounds about right to me.
 
  • #9
Now I'm just stuck on finding the charge of the glass disk.

We are given the amount of electric force acting on the chlorine ion, which has a charge of -1.6e-19.

And with the equation that relates electric force and electric field, F=qE, I can just set the equations up like this:

8e-15=(-1.6e-19)(Q/(3^2*pi))/(2*8.85e-12) and solve for Q, right? Then again, that's an approximation, and I'm not entirely sure if what I did right there is correct (since webassign is telling me that that is the wrong answer [-.000025]). Could it be the sign?

edit: Wait, it might be the sign, I just realized the chlorine ion has a negative charge, and the electric force is TOWARDS the glass disk. Which would also mean that the disk is positive? Need some help for this ;[
 
Last edited:
  • #10
demonhunter19 said:
Now I'm just stuck on finding the charge of the glass disk.

We are given the amount of electric force acting on the chlorine ion, which has a charge of -1.6e-19.

And with the equation that relates electric force and electric field, F=qE, I can just set the equations up like this:

8e-15=(-1.6e-19)(Q/(3^2*pi))/(2*8.85e-12) and solve for Q, right? Then again, that's an approximation, and I'm not entirely sure if what I did right there is correct (since webassign is telling me that that is the wrong answer [-.000025]). Could it be the sign?

edit: Wait, it might be the sign, I just realized the chlorine ion has a negative charge, and the electric force is TOWARDS the glass disk. Which would also mean that the disk is positive? Need some help for this ;[
Your solution looks fine to me, except for the sign. As you correctly point out in your edit, the disk is positively charged. You also might want to check if there is a required number of significant figures, WebAssign is notoriously fickle about significant figures.
 
  • #11
Yep, thank you for your help, Hootenanny!
 

1. What is an electric field involving disks?

An electric field involving disks is a region in space where charged particles experience a force due to the presence of an electric charge. This field is created by a charged disk and can be either uniform or non-uniform depending on the distribution of charge on the disk.

2. How is the electric field strength calculated for a disk?

The electric field strength at a point on a disk is calculated using the formula E = kQ/r^2, where k is the Coulomb's constant, Q is the charge on the disk, and r is the distance from the center of the disk to the point where the field is being measured.

3. What is the direction of the electric field around a disk?

The direction of the electric field around a disk is always perpendicular to the surface of the disk. This means that the field lines will point outward from the disk if the charge is positive and inward if the charge is negative.

4. How does the electric field change as you move away from the center of the disk?

The electric field strength decreases as you move away from the center of the disk. This is because the electric field follows an inverse square law, meaning that the strength of the field decreases proportionally to the square of the distance from the source.

5. Can the electric field of a disk be affected by other nearby charges?

Yes, the electric field of a disk can be affected by other nearby charges. The presence of other charges can cause the field to become non-uniform, meaning that the strength and direction of the field will vary at different points around the disk.

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