Electric fields of a spherical shell

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Homework Help Overview

The discussion revolves around the electric fields produced by a spherical shell, particularly focusing on specific points in relation to the shell's radius. Participants explore concepts related to Gauss's Law and the behavior of electric fields in electrostatic situations.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to determine the electric field magnitudes at various distances from the spherical shell and questions the implications of charge distribution within the shell.
  • Some participants question the assumptions regarding the charge on the shell and the implications of uniform charge distribution.
  • There is a discussion about the calculations for electric field strength at specific points and whether similar methods apply to different distances.
  • Questions arise about the notation for electric field and the availability of resources for electric field formulas.

Discussion Status

The conversation is ongoing, with participants providing confirmations and clarifications regarding the electric field at specific points. Some guidance has been offered on the calculations involved, but there is no explicit consensus on all points raised, particularly regarding the nature of charge distribution.

Contextual Notes

Participants are navigating the complexities of electric fields in relation to spherical shells, with some assumptions about charge distribution and electric field behavior under scrutiny. There is also a request for additional resources related to electric field calculations.

MathewsMD
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My class hasn't delved into Gauss's Law much besides describing conductors at electrostatic equilibrium to have no net electric field or force within itself.

For the picture, the question is:

What are the magnitudes of the electric fields at:

1) r = a
2) r = 3/2 a
3) r = b

Firstly, if r = 0, E = 0, correct?

At r = a, is it correct to assume that the charge on the smaller spherical shell is also 0 since it has no electric fields from it? Is this the correct explanation?

For r = 3/2a, I was having a bit of trouble and was wondering if we are to find

##Q = ρ\frac {4}{3}π [(1.5a)^3 - a^3] ##

Then:

##E = kQ/(1.5a)^2## ?

Would the same steps for r = 3/2a be followed for r = b? Any help regarding how to answer this question, with an explanation (please!), and possibly links to links that you find very informative with tho topic would be greatly appreciated!

Also, does anyone know where I could find a list of electric field formulas for various objects (infinitely thin and long sheets, spheres, quadrupoles, etc.) and accompanying proofs?

And finally, is it incorrect to denote electric field as ε? I've seen both around but E more commonly and was uncertain if it's common convention or not.
 

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MathewsMD said:
Firstly, if r = 0, E = 0, correct?
Yes
At r = a, is it correct to assume that the charge on the smaller spherical shell is also 0 since it has no electric fields from it?
What "smaller spherical shell"? There is only one shell. Do you mean the inner surface of the shell?
The charge is uniformly distributed through a volume. That means the charge on a surface is effectively zero.
For r = 3/2a, I was having a bit of trouble and was wondering if we are to find

##Q = ρ\frac {4}{3}π [(1.5a)^3 - a^3] ##

Then:

##E = kQ/(1.5a)^2## ?
Yes
Would the same steps for r = 3/2a be followed for r = b?
Yes. In fact, you could save yourself a bit of work by solving for a radius which is an arbitrary multiple of a, r = ca, then plug in c = 1.5, c = 2.
Also, does anyone know where I could find a list of electric field formulas for various objects (infinitely thin and long sheets, spheres, quadrupoles, etc.) and accompanying proofs?
Only by doing what you can do - use a search engine.
And finally, is it incorrect to denote electric field as ε? I've seen both around but E more commonly and was uncertain if it's common convention or not.
Pass.
 
haruspex said:
That means the charge on a surface is effectively zero.

Do you mind expanding on this point? If charge is uniformly distributed, won't it be the same everywhere, including on the surface of the inner sphere?
 
MathewsMD said:
Do you mind expanding on this point? If charge is uniformly distributed, won't it be the same everywhere, including on the surface of the inner sphere?
Since it is a finite charge uniformly distributed over a volume, the charge in a given portion is proportional to the volume of that portion. An area has no volume, so contains no charge.
 

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