1. The problem statement, all variables and given/known data Two very large horizontal sheets are 4.25 cm apart and carry equal but opposite uniform surface charge densities of magnitude [tex]\sigma[/tex]. You want to use these sheets to hold stationary in the region between them an oil droplet of mass 364 [tex]\mu[/tex]g that carries an excess of five electrons. Assume that the drop is in vacuum. 2. Relevant equations E = FE / q Fg = mg E = [tex]\sigma[/tex] / 2[tex]\epsilon[/tex]0 [tex]\epsilon[/tex]0 = 8.854 * 10 -12 C2/N*m2 3. The attempt at a solution I calculated the Fg because I know the FE must be equal and opposite of gravity in order to be suspended. I also calculated the net charge of the oil drop which was 5xe- (the charge of one electron) = 8.01 * 10-19 C. I divided the FE by the net charge of the drop to find the Electric Field in N/C. I then multiplied E (electric field) by 2[tex]\epsilon[/tex]0 to solve for [tex]\sigma[/tex] but this is not the correct answer apparently. Where have I went wrong?