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## Homework Statement

"A thin wire with linear charge density λ is surrounded by a conducting cylindrical shell."

(There is a hollow cylinder with a wire though it)

"If the electric field must be zero inside a conductor, is the electric field due to the wire shielded from extending beyond the conducting shell?Find the electric field as a function of distance r from the thin wire."

## Homework Equations

EA = Q

_{enc}/ε

_{0}

Q = P/V

surface area (A) = 2πrl

## The Attempt at a Solution

I'm having more conceptual difficulty with this question than mathematical. There is a charged wire in a conductor, but the inside of the conductor must have an E field of zero (at equilibrium). How does this happen? How does the charge on the conductor rearrange or move to cancel the E field? Do I assume the charge can't leave the wire?

To find the E(r) I would just use a Gaussian surface at different intervals (I know it's zero until r>R of cylinder). After that the Q enclosed is just constant from the surface of the cylinder shell.

Thanks for the help.