Electric fields through parallelepiped

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SUMMARY

The discussion centers on calculating electric fields through a parallelepiped using Gauss's law. The user successfully determines the charge inside the shape but seeks clarification on the interaction of electric fields when the parallelepiped is positioned between infinite parallel plates. The user proposes that the fields from the plates combine through superposition to yield the correct total fields. Additionally, they inquire about the total electric flux if external charges influence the field around the parallelepiped.

PREREQUISITES
  • Understanding of Gauss's law and its application in electrostatics.
  • Familiarity with electric field concepts, particularly in relation to infinite parallel plates.
  • Knowledge of superposition principle in electric fields.
  • Basic grasp of electric flux and its calculation methods.
NEXT STEPS
  • Study the application of Gauss's law in complex geometries, specifically parallelepipeds.
  • Explore the concept of electric field superposition in multi-plate systems.
  • Learn how to calculate electric flux for various charge distributions, including external charges.
  • Investigate the behavior of electric fields in the presence of conductors and dielectrics.
USEFUL FOR

Physics students, electrical engineers, and anyone studying electrostatics or working with electric fields in complex geometrical configurations.

Fluxthroughme
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I have taken my Gauss surface as the front of the shape, with [itex]E_1[/itex] coming through uniformly. I get the right answer for the charge inside the shape, but I'm unsure about b. I imagine a situation that I've drawn could be possible, but I've never seen it before, so I do not know. I'm thinking that the parallelepiped is going through one of the plates involved in an infinite parallel plate set up, with a single infinite plate above them. The two fields would combine as I have labelled, and would, by superposition, give the right total fields at the places they required. If anyone could let me know whether this is fine, or just nonsense, it'd be helpful. Thank you.
 
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If the field were due to charges outside the parallelepiped, what would be the total flux?
 

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