F= ma and E=F/q So i sub, and get ma= Eq then solved for q/m
ma=Eq I divided by m on each side to get q/m= aE. Then a=-9.81 and E= -150. I multiplied. Oh wait okay so I was supposed to get: a/E= q/m. so It would be -9.81/-150 = -0.654. q/m = -0.654 Correct?
Vela. I'm really confused I've been working on this for hours. I know that the gravitational and electric force have to cancel in order for the particle to be hovering.how would another force be included in the equation q/m=a/E ? or am i using the wrong equation?
If the particle hovers, what is its acceleration?well F=ma and E=F/q so E= ma/q
|Felectric| is related to E by E=F/q
and |Fgravity| related to g by F=ma
im not understanding why you have Felectric/ Fgravity=1