Electric Flux and Gauss' Law of point charges

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Homework Help Overview

The problem involves calculating the total electric flux due to two point charges located at specified coordinates through a spherical surface centered at the origin. The context is rooted in the application of Gauss' Law and electric flux concepts.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of electric flux using the formula \(\phi_{E} = \frac{Q_{enclosed}}{\epsilon_{0}}\) and question the correctness of unit conversions and the charges considered within the spherical surface.

Discussion Status

Some participants have shared their calculations and expressed uncertainty about their results, while others have offered suggestions for clarifying the original problem statement and checking unit conversions. There is an ongoing exploration of the assumptions made regarding the charges and their contributions to the flux.

Contextual Notes

There is mention of losing points for incorrect answers in an online homework setting, which may influence participants' approaches to verifying their calculations and understanding the problem.

robbondo
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Homework Statement



A point charge [tex]q_{1} = 4.15 \times 10^-6[/tex] is located on the x-axis at x = 1.80 m, and a second point charge [tex]q_{2} = -5.80 \times 10^-6[/tex] C is on the y-axis at y = 1.10 m. What is the total electric flux due to these two point charges through a spherical surface centered at the origin and with radius r = 1.45 m?
Take the permittivity of free space to be [tex]8.85 \times 10^{-12}\:{\rm C}^{2}/{\rm N \cdot m}^{2}.[/tex]


Homework Equations



[tex]\phi_{E} = \frac{Q_{enclosed}}{\epsilon_{0}}[/tex]




The Attempt at a Solution



I just divided the one charge inside the sphere by epsilon naught.

[tex]\frac{q_{2}}{\epsilon_{0}}[/tex]

So I get, [tex]-6.55 \times 10^{5}[/tex]

I'm sure I screwed something obvious up, any suggestions?
 
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robbondo said:

Homework Equations



[tex]\phi_{E} = \frac{Q_{enclosed}}{\epsilon_{0}}[/tex]

The Attempt at a Solution



I just divided the one charge inside the sphere by epsilon naught.

[tex]\frac{q_{2}}{\epsilon_{0}}[/tex]

So I get, [tex]-6.55 \times 10^{5}[/tex]

I'm sure I screwed something obvious up, any suggestions?

Why are you sure you messed up? Show the calculation you made and also be sure to show your units.
 
I know I'm wrong because this hw's online and I got it wrong, and I loose points for every wrong answer suckily. Well the units for q were nanocoulombs which I changed to coulombs and then epsilon naught is [tex]{\rm C}^{2}/{\rm N \cdot {m}}^{2}[/tex]. So they cancel out do give [tex]{\rm N \cdot m}^{2}/ \rm C}[/tex]

Calculation was [tex]\frac{-5.8 \cdot 10^{-12}}{8.85 \cdot 10^{-12}}[/tex]

crap... I used the wrong changing of units it [tex]1 \cdot 10^{-9}[/tex] coulombs per nanocoulombs... not -6.

Thanks solo.
 
robbondo said:
crap... I used the wrong changing of units it [tex]1 \cdot 10^{-9}[/tex] coulombs per nanocoulombs... not -6.

Thanks solo.

Well, that was easy on me... As a suggestion, when you present a problem in the forum, type it in exactly as it appeared originally. That would have made the SI prefix error easy to spot. Your method was correct!
 

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