Electric flux through a circular plate

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SUMMARY

The discussion focuses on calculating electric flux through a circular plate intersecting a spherical surface. The participants derive the electric flux using the formula Ea1 = Q/(4πE0r²) for a sphere and relate it to the area of the spherical cap created by the intersection. They establish that the flux through the circular surface is equivalent to the flux through the spherical surface, leading to the equation Eas = (Q*a[1-(d/√(a²+d²))])/(2*ε(a²+d²)). The conversation highlights the importance of correctly applying the area of the spherical cap in the calculations.

PREREQUISITES
  • Understanding of electric flux and Gauss's Law
  • Familiarity with spherical geometry and surface area calculations
  • Knowledge of the electric field formula, specifically Ea1 = Q/(4πE0r²)
  • Basic calculus for manipulating equations involving variables
NEXT STEPS
  • Study the derivation of electric flux in spherical coordinates
  • Learn about the application of Gauss's Law in different geometries
  • Explore the concept of spherical caps and their surface area calculations
  • Investigate the relationship between electric field and electric flux in electrostatics
USEFUL FOR

Physics students, electrical engineers, and anyone studying electromagnetism who seeks to understand the principles of electric flux and its calculations through various geometrical shapes.

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http://img508.imageshack.us/img508/7047/problemhi1.jpg

Now I have gone about solving this problem by drawing a sphere with Q centred in it, let's call this sphere A1, now this circle defined by r=5 (lets call this circle C) cuts this sphere perfectly creating a spherical surface let's call As.

Now we know the electric flux through As will be the same as the area defined by the circle C so we can find the electric flux by finding the total electric flux through A and * it by the ratio of As/A.

So now we have: (sorry I don't know latex)
Ea1 = flux through A1 (sphere)
Eas = flux through As (spherical surface)

Eas = Ea1 * As/A1

A1 = 4*Pi*r^2
As = 2*Pi*r(r-d)
r = Sqrt(a^2 + d^2)
r = 5.83
Ea1 = Q/4*Pi*E0*r^2

Eas = Q/4*Pi*E0*r^2 * 2*Pi*r(r-d) / 4*Pi*r^2

Now I haven't bothered to simply it and calculate an answer but does this look correct?
 
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Yeah it looks ok. Funny that they would actually give you the formula for surface area of a spherical cap and even tell you explicitly how to substitute the variables.
 
Well it was the first question in the course, I've only have 1 lecture on the material so I really did need that hint.
 
can anybody explain why flux is taken as (q/4phiepselon r^2) [which is the formula for field]and not as q/epsilon?please reply soon
 
sanjanaraj said:
can anybody explain why flux is taken as (q/4phiepselon r^2) [which is the formula for field]and not as q/epsilon?please reply soon
Probably not!

As implied by your question, it looks like the given solution was in error - in just the way you suspect.
 
i would probably go about this question in the below mentioned way:-

consider a imaginary sphere S centered at Q,the circle cuts the sphere creating a spherical surface A.The flux through the circle is same as the flux through the spherical surface.
let the radii of the sphere subtend an angle 2(alpha) at the centre such that
tan(alpha) = a/d
now area of spherical surface,As=2*phi*a(1-cos(alpha) )
flux through the spherical surface = (q/epsilon)*2*phi*a(1-cos(alpha)) / {4*phi*(a^2 + d^2)
thus flux through the circular surface =
{q*a[1-(d/root(a^2+d^2)]}/{2*epsilon*(a^2+d^2)}is it correct?
 
I think AS should be given by:A_S=2\pi Rh=2\pi R(R-d)=2\pi R^2(1-d/R)=2\pi R^2(1-\cos(\alpha))=2\pi (a^2+d^2)(1-\cos(\alpha))\,.
 

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