Electric flux through a circular plate

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Homework Help Overview

The discussion revolves around calculating electric flux through a circular plate, specifically in the context of a problem involving a charge and spherical surfaces. Participants are exploring the relationship between the electric field and flux, as well as the geometric considerations of the problem.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss various methods to relate the electric flux through a spherical surface to that through a circular area. There are attempts to derive formulas based on geometric relationships and electric field equations. Questions arise regarding the appropriate formulas to use for calculating flux and the reasoning behind them.

Discussion Status

Some participants have provided insights and hints that may guide others in their understanding of the problem. There is an ongoing exploration of different interpretations of the flux calculation, and some participants express uncertainty about the correctness of their approaches.

Contextual Notes

There is mention of limited prior knowledge on the topic, as it is an early question in the course. Participants are also questioning the assumptions behind the formulas used for electric flux and field strength.

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http://img508.imageshack.us/img508/7047/problemhi1.jpg

Now I have gone about solving this problem by drawing a sphere with Q centred in it, let's call this sphere A1, now this circle defined by r=5 (lets call this circle C) cuts this sphere perfectly creating a spherical surface let's call As.

Now we know the electric flux through As will be the same as the area defined by the circle C so we can find the electric flux by finding the total electric flux through A and * it by the ratio of As/A.

So now we have: (sorry I don't know latex)
Ea1 = flux through A1 (sphere)
Eas = flux through As (spherical surface)

Eas = Ea1 * As/A1

A1 = 4*Pi*r^2
As = 2*Pi*r(r-d)
r = Sqrt(a^2 + d^2)
r = 5.83
Ea1 = Q/4*Pi*E0*r^2

Eas = Q/4*Pi*E0*r^2 * 2*Pi*r(r-d) / 4*Pi*r^2

Now I haven't bothered to simply it and calculate an answer but does this look correct?
 
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Yeah it looks ok. Funny that they would actually give you the formula for surface area of a spherical cap and even tell you explicitly how to substitute the variables.
 
Well it was the first question in the course, I've only have 1 lecture on the material so I really did need that hint.
 
can anybody explain why flux is taken as (q/4phiepselon r^2) [which is the formula for field]and not as q/epsilon?please reply soon
 
sanjanaraj said:
can anybody explain why flux is taken as (q/4phiepselon r^2) [which is the formula for field]and not as q/epsilon?please reply soon
Probably not!

As implied by your question, it looks like the given solution was in error - in just the way you suspect.
 
i would probably go about this question in the below mentioned way:-

consider a imaginary sphere S centered at Q,the circle cuts the sphere creating a spherical surface A.The flux through the circle is same as the flux through the spherical surface.
let the radii of the sphere subtend an angle 2(alpha) at the centre such that
tan(alpha) = a/d
now area of spherical surface,As=2*phi*a(1-cos(alpha) )
flux through the spherical surface = (q/epsilon)*2*phi*a(1-cos(alpha)) / {4*phi*(a^2 + d^2)
thus flux through the circular surface =
{q*a[1-(d/root(a^2+d^2)]}/{2*epsilon*(a^2+d^2)}is it correct?
 
I think AS should be given by:[tex]A_S=2\pi Rh=2\pi R(R-d)=2\pi R^2(1-d/R)=2\pi R^2(1-\cos(\alpha))=2\pi (a^2+d^2)(1-\cos(\alpha))\,.[/tex]
 

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