Electric Flux through Planar Surfaces

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SUMMARY

The discussion focuses on calculating electric flux through two perpendicular planar surfaces with areas of 1.2 m² and 3.5 m², subjected to a uniform electric field of 246 N/C. The correct formula for electric flux, Φ = EAcos(Θ), was clarified, emphasizing that Θ is the angle between the electric field and the normal to the surface, not the surface itself. The initial miscalculation of 169.3197 Nm²/C was corrected by understanding this angle distinction, leading to accurate flux calculations for both surfaces.

PREREQUISITES
  • Understanding of electric flux and its formula, Φ = EAcos(Θ)
  • Knowledge of vector angles in physics, particularly relating to surfaces
  • Familiarity with uniform electric fields and their properties
  • Basic skills in trigonometry for angle calculations
NEXT STEPS
  • Study the concept of electric flux in greater detail, focusing on various surface orientations
  • Learn about the implications of electric field direction on flux calculations
  • Explore examples of electric flux in different geometrical configurations
  • Investigate the applications of electric flux in Gauss's Law
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone seeking to deepen their understanding of electric flux and its calculations in planar surfaces.

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Homework Statement



The drawing shows an edge-on view of two planar surfaces that intersect and are mutually perpendicular. Surface 1 has an area of 1.2 m², while surface 2 has an area of 3.5 m². The electric field E in the drawing is uniform and has a magnitude of 246 N/C.

Image:

http://img513.imageshack.us/img513/9947/physicspf4.jpg

What's the electric flux through surface 1? What about surface 2?

Homework Equations



[tex]\Phi = EAcos\Theta[/tex]

The Attempt at a Solution



For #1, I attempted to do 246*1.2*cos(55°), which is incorrect at 169.3197 Nm²/C.

What exactly am I screwing up here?
 
Last edited by a moderator:
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If the field is perpendicular to the surface then flux is just EA. From this we conclude that the angle in your formula is the angle that the field makes with a normal to the surface, not the angle it makes with the surface.
 
Dick said:
If the field is perpendicular to the surface then flux is just EA. From this we conclude that the angle in your formula is the angle that the field makes with a normal to the surface, not the angle it makes with the surface.

Yeah, I was thinking things through and got my angles a bit mixed in the process, as you can see.

Got it now - thanks.
 

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