Electric flux through surface of a cube?

  • Thread starter m84uily
  • Start date
  • #1
33
0

Homework Statement


A 10nC point charge is at the center of a 2mx2mx2m. What is the electric flux through the top surface of the cube?


Homework Equations



int(EA) = (Qin)/(ε0)

The Attempt at a Solution



int(EA) = EA + EA + EA + EA + EA + EA = 6EA

A = 4m^2

Qin = 10nC

ε0 = 8.99x10^-12

6EA = (10x10^-9)/(8.99x10^-12)

E = (10x10^-9)/((8.99x10^-12)(6)(A))

E = (10x10^-9)/((8.99x10^-12)(6)(4))

E = 3745

Then for just the top surface

Etop = 3745/6 = 624

Where did I go wrong this time? XD Thanks in advance!
 

Answers and Replies

  • #2
1,384
0
You did not find what the question asked. Read the question again.
 
  • #3
gneill
Mentor
20,826
2,805
The problem asked for the flux. Why are you trying to find the field?
 

Related Threads on Electric flux through surface of a cube?

Replies
1
Views
2K
  • Last Post
Replies
10
Views
15K
  • Last Post
Replies
6
Views
11K
  • Last Post
Replies
3
Views
19K
  • Last Post
Replies
0
Views
3K
  • Last Post
Replies
7
Views
4K
  • Last Post
Replies
2
Views
7K
  • Last Post
Replies
1
Views
39K
  • Last Post
Replies
4
Views
19K
  • Last Post
Replies
3
Views
6K
Top