Electric flux through surface of a cube?

m84uily

1. Homework Statement
A 10nC point charge is at the center of a 2mx2mx2m. What is the electric flux through the top surface of the cube?

2. Homework Equations

int(EA) = (Qin)/(ε0)

3. The Attempt at a Solution

int(EA) = EA + EA + EA + EA + EA + EA = 6EA

A = 4m^2

Qin = 10nC

ε0 = 8.99x10^-12

6EA = (10x10^-9)/(8.99x10^-12)

E = (10x10^-9)/((8.99x10^-12)(6)(A))

E = (10x10^-9)/((8.99x10^-12)(6)(4))

E = 3745

Then for just the top surface

Etop = 3745/6 = 624

Where did I go wrong this time? XD Thanks in advance!

Related Introductory Physics Homework Help News on Phys.org

zorro

You did not find what the question asked. Read the question again.

gneill

Mentor
The problem asked for the flux. Why are you trying to find the field?

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