# Electric flux through surface of a cube?

m84uily

## Homework Statement

A 10nC point charge is at the center of a 2mx2mx2m. What is the electric flux through the top surface of the cube?

## Homework Equations

int(EA) = (Qin)/(ε0)

## The Attempt at a Solution

int(EA) = EA + EA + EA + EA + EA + EA = 6EA

A = 4m^2

Qin = 10nC

ε0 = 8.99x10^-12

6EA = (10x10^-9)/(8.99x10^-12)

E = (10x10^-9)/((8.99x10^-12)(6)(A))

E = (10x10^-9)/((8.99x10^-12)(6)(4))

E = 3745

Then for just the top surface

Etop = 3745/6 = 624

Where did I go wrong this time? XD Thanks in advance!