1. The problem statement, all variables and given/known data In (Figure 1) take the half-cylinder's radius and length to be 3.4 cm and 15 cm, respectively. If the electric field has magnitude 5.3 kN/C, find the flux through the open half-cylinder. The surface here is the right half of the surface of a full cylinder. The surface does not include the rectangle which is the opening to the half-cylinder. Hint: You don't need to do an integral! Why not? 2. Relevant equations φ = Qenc / ε0 = ∫E⋅dA = EA 3. The attempt at a solution So I simply took my flux equation to be EA since its a half cylinder with constant E and symmetry. Through this I got 5.3 kN/C * (π(3.4cm)2+π(3.4cm)(15cm)) = 1041.65 kN/C m2. This is apparently wrong? What is proper way of handling this problem as I though I was doing it correctly.