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[SOLVED] Electric potential and electric field
A - 10.0 nC point charge and a + 20.0nC point charge are 15 cm apart on the x-axis.
What is the magnitude of the electric field at the point on the x-axis, between the charges, where the electric potential is zero?
sumE = E(of -10) + E (of 20)
E = kq/r^2
SumV = V(-10) +V(20)
V = kq/r
let the distance at which V = 0 between the charge be x
SumV = V(-10) +V(20) = 0
k { (-10 *10^-9/0.15 - x) + (20 *10^-9/ x)} = 0
solve for x
x = 0.1
0.15 - x = 0.05
SumE = E(-10) +E(20)
k { (-10 *10^-9/(0.15 - x)^2) + (20 *10^-9/ (x)^2)} = SumE
substitute x = 0.1
Sum E= 18000 V
i don't think this is the right answer
i think i am doing something wrong
Homework Statement
A - 10.0 nC point charge and a + 20.0nC point charge are 15 cm apart on the x-axis.
What is the magnitude of the electric field at the point on the x-axis, between the charges, where the electric potential is zero?
Homework Equations
sumE = E(of -10) + E (of 20)
E = kq/r^2
SumV = V(-10) +V(20)
V = kq/r
The Attempt at a Solution
let the distance at which V = 0 between the charge be x
SumV = V(-10) +V(20) = 0
k { (-10 *10^-9/0.15 - x) + (20 *10^-9/ x)} = 0
solve for x
x = 0.1
0.15 - x = 0.05
SumE = E(-10) +E(20)
k { (-10 *10^-9/(0.15 - x)^2) + (20 *10^-9/ (x)^2)} = SumE
substitute x = 0.1
Sum E= 18000 V
i don't think this is the right answer
i think i am doing something wrong