# Electric potential at an unknown point

miyayeah

## Homework Statement

The electric field inside a parallel plate capacitor is measured to be E= -3500 N/C i. The electric potential at point XA = 3.00 m is measured to be 1500V. What is the electric potential at point XB = 0 m?

V=E⋅s

## The Attempt at a Solution

I think I need to relate the given point to the actual point within the electric field, so I did:

s= V/E = (1500V) / (3500N/C) = 2.333 m
I am not how I should go with this problem. Any help would be appreciated!

Last edited:

Homework Helper
V=E⋅s
is good. So is s= V/E . But V is not -3500 N/C And E is not 1500 V.

Always check the dimensions of what you write down !

Perhaps you can make a sketch showing the positions, E and V ?

miyayeah
is good. So is s= V/E . But V is not -3500 N/C And E is not 1500 V.

Always check the dimensions of what you write down !

Perhaps you can make a sketch showing the positions, E and V ?
Thank you for pointing that out. I edited it now.

If I were to sketch, I would draw the electric potential increasing from the negative to the positive end, and the electric field vector going from the positive to the negative end.
I think I am mainly confused about where I should put the positions, because I'm not sure if X=0 mean the position is at the negative plate.