Electric Potential Difference and electric field

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 2K views
Soccerdude
Messages
6
Reaction score
0

Homework Statement



A uniform electric field points in the –y direction with magnitude 325 V/m. Find the electric potential difference VB-VA between the points A at (-0.200, -0.300) m and B at (0.400, 0.500) m.

Homework Equations



∆V=-int(E . dl)
(Dot Product)

The Attempt at a Solution



∆V=-int(0,1)[(325)cos(36.87)dl]

∆V=-260[l](0,1)=-260 V

Am I doing this correctly?
 
Physics news on Phys.org
Yes. Looks like you chose a straight line path between the initial and final points, which is a good choice. Any path would do.
 
If I were to choose a different path, is this how I would set it up?

∆V=-(int(0,.6)[325cos(90)dl]+int(0,.8)[325cos(0)dl])

Much Appreciated
 
Yes. Good. I noticed you switched the sign outside the integral for the part parallel to the y-axis which goes along with the angle of zero in the cosine. Alternately, of course, you could keep the negative sign in front, but use an angle of 180 degrees as you go upward against E.