Electric Potential Energy and Electric Potential Difference

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SUMMARY

The discussion centers on calculating the work required to move a charge of -4.0 microcoulombs between two parallel plates charged by a 12-V battery. The initial calculation of work done (w = q x V) yields -4.8 x 10^-5 J, indicating work is done against the force of repulsion. However, participants highlight the necessity of additional information, such as the capacitance of the plates, their area, and the distance between them, to accurately determine the electric potential difference and work done. The consensus emphasizes that the electric potential from the battery does not guarantee a uniform electric field necessary for the calculation.

PREREQUISITES
  • Understanding of electric potential energy and electric potential difference
  • Familiarity with the formula for work done in electric fields (w = q x V)
  • Knowledge of parallel plate capacitor concepts, including capacitance
  • Basic principles of electric fields and charge distribution
NEXT STEPS
  • Research the concept of capacitance in parallel plate capacitors
  • Learn how to calculate electric fields between charged plates
  • Study the relationship between electric potential and work done on charges
  • Explore the effects of charge distribution on electric potential in practical scenarios
USEFUL FOR

Students and professionals in physics, electrical engineering, and anyone interested in understanding electric potential energy and its applications in circuit analysis.

predentalgirl1
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A pair of parallel plates is charged by a 12-V battery. How much work is required to move a particle with a charge of --4.0 microcoulombs (MC) from the positive to the negative plate?








Given that,
Emf = 12 V
q = -4 x 10 -6 C
I have,
Work done (w) = q x V
= -4 x 10 -6 x 12
= - 4.8 x 10-5 J ?
‘-‘sign indicates that work is done against the force of
repulsion


Is my work/answer correct??
 
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help please!
 
you seem to be missing some information. what is the capacitance of the parallel plate? or, what is the area of the plates and the distance between the plates?

YOU CAN'T ASSUME THAT THE ELECTRIC POTENTIAL OF THE BATTERY IS GOING TO CREATE A PERFECT CHARGE DISTRIBUTION TO CREATE AN ELECTRIC FIELD NEEDED TO FIGURE OUT THE WORK. IN OTHER WORDS...

V DOES NOT EQUAL -WORK/Q WITH THE INFORMATION YOU'VE GIVEN UNLESS YOU'RE TAKING SOME TYPE OF SURVEY COURSE...HAHAHA.
 
Last edited:

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