Electric Potential Homework: 3000V Needed for 0.1cm Spark

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Homework Help Overview

The problem involves determining the potential difference required to create a spark across a 0.1 cm gap in a spark plug, given the breakdown strength of air. The context is rooted in electric potential and electric fields.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the formula V = -Ed and express confusion about the comparison to 1 m. Questions arise regarding the omission of the negative sign in the context of calculating potential difference and the interpretation of electric potential versus potential energy.

Discussion Status

The discussion is exploring the meaning of the formula and the relationship between electric field strength and potential difference. Some participants are questioning the treatment of signs in potential calculations and the distinction between potential and potential energy. There is no explicit consensus, but there is an ongoing examination of these concepts.

Contextual Notes

Participants note that the problem may involve assumptions about the direction of the electric field and the nature of potential versus potential energy, which are not fully defined in the problem statement.

lha08
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Homework Statement


The gap in the spark plug of the car is 0.1 cm. What potential difference is needed to produce a spark given that the breakdown strength of air is 3X10^6 V/m.


Homework Equations





The Attempt at a Solution


I'm sort of confused by what they're asking...like i tried using the formula V= -Ed but then apparently in the answers, it says 'for 1 m, voltage difference is 3X10^6 V. For 0.1 cm, voltage difference is 0.001 X (3X10^6)= 3000V.
I don't understand why do we need to compare it to 1 m and why when they calculated it, they didn't place a negative sign like in the formula...
 
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lha08 said:
I don't understand why do we need to compare it to 1 m and why when they calculated it,
They are just trying to explain the meaning of the formula. The electric field is given as XXX volts/meter, so the voltage difference is proportional to the distance. It's equivalent to just using the formula.
they didn't place a negative sign like in the formula...
All they want is the magnitude of the potential difference. The sign of the potential difference depends on the direction of the field, which is not given.
 
Doc Al said:
They are just trying to explain the meaning of the formula. The electric field is given as XXX volts/meter, so the voltage difference is proportional to the distance. It's equivalent to just using the formula.

All they want is the magnitude of the potential difference. The sign of the potential difference depends on the direction of the field, which is not given.

I'm noticing that when I'm doing problems and they ask for the change in electric potential, for some reason, they are always taking the magnitude while I'm always adding a positive or negative sign..like for example, when an electron is moving with the field (its negative work) but then I thought that the potential should also be negative since it's losing potential energy...but its not...is there any particular reason as to why this is?
 
lha08 said:
like for example, when an electron is moving with the field (its negative work) but then I thought that the potential should also be negative since it's losing potential energy...but its not...is there any particular reason as to why this is?
Don't confuse potential with potential energy. An electron is negative, so its potential energy decreases as it moves in the direction of the field even though the potential is increasing.
 

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