(adsbygoogle = window.adsbygoogle || []).push({}); 1. A wire of finite length that has a uniform linear charge density [tex]\lambda[/tex] is bent into the shape shown in the figure below. Find the electric potential at point O.

The image has the setup.

2. The answer is [tex]k\lambda\pi (\pi + 2ln3) [/tex] How the hell do I get this? The primary equation I am using is of course [tex] \int \frac{dq}{r} [/tex] where finding a proper dq is the chore.

3. Okay, so this problem is driving me a little bit crazy. I tried integrating the electric potential equation with respect to the loop, integrating from 0 to [tex]\pi [/tex] which gives me [tex]k\lambda\pi [/tex]

It makes sense that this is incorrect as the the linear charge density is going to be spread across the entire wire. However, whenever I try to account for the rest of the wire outside of the loop I get nonsensical and incorrect answers and integrations. I am fairly certain this is what I need to do, I am just clueless as to how to go about it

How do I set this up ? Thanks for any help you can provide.

fixing latex if it something looks funny

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# Homework Help: Electric Potential, Linear charge with a loop

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