Electric Potential of 3 point charges

[Kittlinljd]

1. The arrangement of charges shown in the figure is called a linear electric quadrupole. The positive charges are located at +-s. Notice that the net charge is zero.
Find an expression for the electric potential on the x-axis at distances y>>s.

Homework Equations

V= \sum1/4pi \epsilon0 * qi/ri

The Attempt at a Solution

Im just not sure how to go about modeling this equation.. otherwise I don't know were to start.
I have tried: 1/4pi\epsilon0 *Q/y thinking that it was a simple question, and I now understand that I should pick a s-value and use that to come up with the radius. However, I am stuck on how.
Thanks

 

[CompuChip]

Let's start by finding expressions for the r_i.

Can you express them in terms of y and/or s?

 

[Spinnor]

1. The arrangement of charges shown in the figure is called a linear electric quadrupole. The positive charges are located at +-s. Notice that the net charge is zero.
Find an expression for the electric potential on the x-axis at distances y>>s.

Homework Equations

V= \sum1/4pi \epsilon0 * qi/ri

The Attempt at a Solution

Im just not sure how to go about modeling this equation.. otherwise I don't know were to start.
I have tried: 1/4pi\epsilon0 *Q/y thinking that it was a simple question, and I now understand that I should pick a s-value and use that to come up with the radius. However, I am stuck on how.
Thanks

You have the definition of the potential. Say I sit at x=0, y=10. Ignore the constants but not the charge and distance. You should be able to write down the potential at this point, (remember the distance from x=0, y=10 to each charge are 10 + s, 10, 10-s. Your general formula must take into account the fact that the charges are not at the same place.

V(y=10) = 1/(10 + s) -2/10 + 1/(10 - s)

In general V(y) = 1/(y + s) - 2/y + 1/(y - s).

 

[Kittlinljd]

so I change the constants to -s or s depending on which direction on the direction on the y axis? that makes sense.
What I tried was V = K \sumQ/(y+s) -2Q/(y) + Q/(y-s) , and it said that the answer does not depend on the variable s. Would this have something to do with Q= 2qs^2, being the electric quadrupole moment.

 

[CompuChip]

You solved the problem for a point on the y-axis, like Spinnor said in his example.

However, you want to take a point on the x-axis.
Did you read my post (#2) ?

 

[Kittlinljd]

ahhhh, okay so now I see so I get:
K* Q/(y^3)
which is the answer masteringphysics took!
Thanks So much!

 

[CompuChip]

I assume that you worked this out using the Pythagorean theorem, and found that s cancels out