Electric potential of electric dipole at large distance

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SUMMARY

The electric potential of an electric dipole at a large distance is expressed as V = (qa cos(θ))/(4πεr²), where 'a' represents the separation of the two charges ±q, and 'r' is the distance from the dipole. As the distance 'r' approaches infinity, the potential approaches zero, since the contributions from both charges cancel each other out. This conclusion is derived from the approximation that at large distances, the point of interest is equidistant from both charges, leading to V = kq/r + k(-q)/r = 0.

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blueyellow

Homework Statement



write down an expression for the electric potential of an electric dipole at a large distance

Homework Equations



V=(qa cos(theta))/(4 pi epsilon r^2)

The Attempt at a Solution



is 'r' the distance they are talking about or is it 'a'?
either way, if i substitute in a=infinity or r=infinity, the above equation just blows up
 
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hi blueyellow! :smile:

(have an infinity: ∫ and a theta: θ and a pi: π and an epsilon: ε and try using the X2 icon just above the Reply box :wink:)
blueyellow said:
is 'r' the distance they are talking about or is it 'a'?
either way, if i substitute in a=infinity or r=infinity, the above equation just blows up

a is the separation of the two ±q charges (so qa is the dipole moment)

(and 1/∞2 = 0 :wink:)
 
and you can also find it like this:

as r>>a ... so distance of point at r is approx same from both charge ie ≈ r

so V = kq/r + k(-q)/r = 0
 

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