Electric vs Magnetic Field: Transferring Energy

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SUMMARY

The discussion clarifies that electric fields can transfer energy to objects, while magnetic fields cannot perform work in the classical sense. According to the Lorentz force law, the force on a charged particle in a magnetic field is always perpendicular to its velocity, preventing energy transfer. However, current distributions in magnetic fields can possess energy due to internal electric forces, as detailed in Jackson's "Classical Electrodynamics" and Griffiths' "Introduction to Electrodynamics".

PREREQUISITES
  • Understanding of classical electrodynamics
  • Familiarity with the Lorentz force law
  • Knowledge of energy concepts in magnetic fields
  • Access to Jackson's "Classical Electrodynamics" and Griffiths' "Introduction to Electrodynamics"
NEXT STEPS
  • Study the Lorentz force law in detail
  • Explore energy calculations in magnetic fields using W=\frac{1}{2}\int \textbf{H}\cdot\textbf{B} d^3x
  • Review examples from Griffiths' "Introduction to Electrodynamics" related to magnetic fields
  • Investigate discussions on magnetic field energy transfer in online forums
USEFUL FOR

Students and professionals in physics, electrical engineers, and anyone interested in the principles of energy transfer in electromagnetic fields.

adiputra
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I just want to clarify whether electric field is the one which can transfer its energy to some object while magnetic field cannot. If yes, how come magnetic field cannot transfer its energy?
 
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adiputra said:
I just want to clarify whether electric field is the one which can transfer its energy to some object while magnetic field cannot. If yes, how come magnetic field cannot transfer its energy?

Magnetic fields cannot transfer energy to objects because (classically at least) they can't do any work. In classical electrodynamics, the only sources/sinks are are static or dynamic (currents) charge distributions. The fundamental force law governing how these sources/sinks interact with magnetic fields is the Lorentz force law, which says that the force on a charge element is always perpendicular to the charge's instantaneous velocity, \textbf{v}=\frac{d\textbf{r}}{dt}, and hence the magnetic field never does any work.

However, a current distribution placed in a magnetic field will have some associated energy, W=\frac{1}{2}\int \textbf{H}\cdot\textbf{B} d^3x (See section 5.16 of Jackson's Classical Electrodynamics 3rd ed. for a good brief discussion of energy in a magnetic field), since there are forces at play inside the distribution (usually electric) which do an amount of work which depends on the external magnetic field (See example 5.13 of Griffiths' Introduction to Electrodynamics 3rd ed.).
 
Just search "magnetic field" here and you'll turn up many discussions about your question.
 

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