Electrical Energy Dissipation Across Resistors

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The discussion revolves around calculating electrical energy dissipation across resistors in a circuit. For the 5.0-Ω and 9.0-Ω resistors, participants emphasize the need to determine the voltage difference and current through the resistors to find power dissipation. The power output of the 16.0-V battery and the energy conversion rate of the 8.0-V battery are also critical points of inquiry. Participants suggest summing the voltage sources and resistances in series to find the current, but caution is given regarding the direction of voltages affecting calculations. Accurate application of the power formulas is essential for correct results.
Yosty22
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Homework Statement



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A). What is the total rate at which electrical energy is dissipated in the 5.0−Ω resistor?
B). What is the total rate at which electrical energy is dissipated in the 9.0−Ω resistor?
C). What is the power output of the 16.0-V battery?
D). At what rate is electrical energy being converted to other forms in the 8.0-V battery?


Homework Equations



P=V_ab(I)=I^2R=V_ab^2/R

The Attempt at a Solution



I can't figure this out at all. For part A, I need the voltage difference and the resistance. How would I find the voltage difference? And does the 5 ohm resistor mean that the resistance is 5 over the resistor? In which case I need to find the voltage drop across the resistor. How do I do this?
 
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Just sum up all of the voltage sources around the loop and all the resistances, since they're all in series, and you'll have the current around the loop. Can you take it from there?
 
Ok, so I added up the voltages (24V) and added up the resistance (17 ohms). I then did V/R to get I=1.412A. Then, I used the equation P=V_ab * I and got P=120W, but it is wrong. What am I doing here?
 
You are not taking into account the direction of the voltages.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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